由于我的SpringBoot应用程序,Swagger UI没有显示,每个端点都需要2个查询参数

问题描述 投票:0回答:1

我的Spring Boot应用程序的所有端点都希望有2个查询参数(http://localhost:myapplcation/getAll?pid=1101&token=jdu191092kj11),所有端点都按预期工作。但是,如果我传递2个查询参数,我就能看到api swagger(http://localhost:8080/v2/api-docs?pid=1101&token=jdu191092kj11

此Swagger UI的问题..没有显示http://localhost:8080/swagger-ui.html

我该如何解决?

下面是代码:

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurationSupport;
import springfox.documentation.builders.ApiInfoBuilder;
import springfox.documentation.builders.RequestHandlerSelectors;
import springfox.documentation.service.ApiInfo;
import springfox.documentation.service.Contact;
import springfox.documentation.spi.DocumentationType;
import springfox.documentation.spring.web.plugins.Docket;
import springfox.documentation.swagger2.annotations.EnableSwagger2;
import static springfox.documentation.builders.PathSelectors.regex;

@Configuration
@EnableSwagger2
public class SwaggerConfig extends WebMvcConfigurationSupport {
    @Bean
    public Docket productApi() {
        return new Docket(DocumentationType.SWAGGER_2)
                .select()
                .apis(RequestHandlerSelectors.basePackage("com.springframework.controllers"))
                .paths(regex("/product.*"))
                .build()
                .apiInfo(metaData());
    }
    private ApiInfo metaData() {
        return new ApiInfoBuilder()
                .title("Spring Boot REST API")
                .description("\"Spring Boot REST API for Online Store\"")
                .version("1.0.0")
                .license("Apache License Version 2.0")
                .licenseUrl("https://www.apache.org/licenses/LICENSE-2.0\"")
                .contact(new Contact("John Thompson", "https://springframework.com", "[email protected]"))
                .build();
    }
    @Override
    protected void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("swagger-ui.html")
                .addResourceLocations("classpath:/META-INF/resources/");

        registry.addResourceHandler("/webjars/**")
                .addResourceLocations("classpath:/META-INF/resources/webjars/");
    }
}
java spring spring-boot query-parameters webjars
1个回答
0
投票

在正则表达式中,您要添加产品。*,但在url路径中您没有产品字词。

让我们简单点,看看它是否像下面那样工作

 @Bean
    public Docket api() {
    return new Docket(DocumentationType.SWAGGER_2)
        .apiInfo(metaData())
         .apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
        .paths(PathSelectors.any())
        .build();
    }
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