如果Laravel中的值不为null,如何验证输入字段

问题描述 投票:6回答:4

我正在尝试使用laravel 5.4创建和更新用户

这是为创建用户添加的验证。有用。

$this->validate($request, [
    'name' => 'required|max:255',
    'email' => 'required|email|max:255|unique:users',
    'password' => 'required|min:6|confirmed',
]);

更新时,不需要密码字段。但是如果密码字段不为空,则验证min:6并确认规则。尝试与sometimes ..但没有工作..

$this->validate($request, [
    'name' => 'required|max:255',
    'email' => 'required|email|max:255|unique:users,email,'.$id,
    'password' => 'sometimes|min:6|confirmed',
]);
php laravel laravel-5.4 laravel-validation
4个回答
21
投票

尝试使用nullable作为规则

'password' => 'nullable|min:6|confirmed',

https://laravel.com/docs/5.4/validation#a-note-on-optional-fields


1
投票

In case column is nullable

'password' => 'nullable|min:6|confirmed',

@Rejinderi的回答是正确的!

In case column is not nullable (This may help other)

'password' => 'sometimes|required|min:6|confirmed',

Result

username = 'admin',
password = null // fail- required

username = 'admin',
password = 123 // fail- min:6

username = 'admin' // pass- validate only exist

0
投票

根据密码字段创建规则。仅在存在密码字段时才进行验证。

if ($request->input('password')) {
    $rules = [
        'name' => 'required|max:255',
        'email' => 'required|email|max:255|unique:users,email,'.$id,
        'password' => 'required|min:6|confirmed',
    ];
} else {
    $rules = [
        'name' => 'required|max:255',
        'email' => 'required|email|max:255|unique:users,email,'.$id
    ];
}

$this->validate($request, $rules);

0
投票

我就是这样做的:

//For new or create :
$this->validate($request, [
    'name' => 'required|max:255',
    'email' => 'required|email|max:255|unique:users',
    'password' => 'required|min:6|confirmed',
]);

//For edit or update:
$this->validate($request, [
    'name' => 'required|max:255',
    'email' => 'required|email|max:255|unique:users',
    'password' => 'min:6|confirmed',//just remove required from password rule
]);

说明: 这样,只有在请求中定义(存在)时才会验证该值 如果使用nullable,则验证器将接受null作为值(我认为这是不可接受的) 如果从更新中删除密码验证,则根本不会验证此输入,并且将接受任何值(这也是不可接受的);

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