python subprocess不会运行phantomjs，但可以在linux命令行中运行

Question

当我在CENTOS 7服务器上运行它时，它可以从bash运行：

[myserver]$ /home/phantomjs-2.1.1-linux-x86_64/bin/phantomjs /home/phantomjs-2.1.1-linux-x86_64/bin/thumbnails.js -3933029 91 q5975 "http://mysite/explore?viz=summary_slider"
Rendered 'http://mysite/explore?viz=summary_slider' at '/home/thumbnails/th-3933029c91q5975.png'

但是如果我在python中使用子进程执行此操作，则会出现错误：

import subprocess
phantomjs_call = u'{0}phantomjs {0}thumbnails.js {1}'.format(phantomjspath, link)
rendered = subprocess.check_output(phantomjs_call.split())

回报

/home/phantomjs-2.1.1-linux-x86_64/bin/phantomjs /home/phantomjs-2.1.1-linux-x86_64/bin/thumbnails.js "http://mysite/explore?viz=summary_checkbox"
Unable to render '"http://mysite/explore?viz=summary_checkbox"'

子进程args有什么奇怪的东西吗？还是shell环境不对？

接下来，我调整它并将完整的字符串作为一个参数传递，然后我得到了OSError：

rendered = subprocess.check_output(phantomjs_call)
# didn't split this into multiple arguments
>>>[Errno 2] no such file or directory"

Answer 1

那个怎么样

import subprocess
phantomjs_call = '{0}phantomjs {0}thumbnails.js {1}'.format(phantomjspath, link)
print(subprocess.check_output(phantomjs_call), shell=True)

要么

import os
phantomjs_call = '{0}phantomjs {0}thumbnails.js {1}'.format(phantomjspath, link)
print(os.system(phantomjs_call))

Answer 2

因此，在尝试了subprocess的许多不同的变化后，这是与phantomjs一起使用的：subprocess32 !!!

    import subprocess32 # not the default version; this supports timeouts
    for (_id, link) in link_list:        
        phantomjs_call = u'{0}phantomjs {0}thumbnails.js {1} {2} {3} {4}'.format(phantomjspath, _id, link)
        """note: this generates a string like
/home/phantomjs-2.1.1-linux-x86_64/bin/phantomjs 
/home/phantomjs-2.1.1-linux-x86_64/bin/thumbnails.js 51514 
"http://mysite/explore?viz=summary_text"
        """
        try:
            process = subprocess32.Popen(phantomjs_call, shell=True, stdout=subprocess32.PIPE)
            # make sure phantomjs has time to download/process all the pages in the list
            # but if we get nothing after 180 sec, just move on
        except Exception as e:
            print(phantomjs_call)
            print('Popen failed', e)

        try:
            output, errors = process.communicate(timeout=180)
        except Exception as e:
            if debug == True: 
                print("\t\tException: %s" % e)
            process.kill()
            return "\t\tException: {0}".format(e)
        # output will be weird, decode to utf-8 to save heartache
        phantom_output = []
        for out_line in output.splitlines():
            phantom_output.append( out_line.decode('utf-8') )

这是python2.7 - 它在python3中可能更容易，但是在这里保存它因为我花了很多试验和错误来使subprocess32与phantomjs一起工作。

另外 - 我没有共享thumnails.js文件，但它是javascript，可以根据需要将命令行输入解析为phantomjs，并使用这些参数构造文件名。