如何对齐Google地图经度的ggmap CRS

问题描述 投票:3回答:1

尽管有很多CRS预测的帖子,等等,我无法阻止我的小镇沉没。

[如果我转到Google Maps并输入-35.016, 117.878,则奥尔巴尼镇位于干旱土地上(如下图所示):enter image description here

如果我在R中输入纬度/经度,并尝试使用简单的功能包和ggmap进行映射,则该城镇位于大海中:

library(tidyverse)
library(sf)
library(lwgeom) 
library(ggmap) 

lat <- c(-35.016)
lon <- c(117.878)
df <- tibble(lon,lat) %>% st_as_sf( coords = c("lon", "lat"), crs = 4326)

bbox_aus <- c(left = 113.338953078, bottom = -43.6345972634, right = 153.569469029, top = -10.6681857235)
ggmap_aus <- ggmap(get_stamenmap(bbox_aus, zoom = 5, maptype = "toner-background"))  

ggmap_aus + 
  geom_sf(data = df, colour = "red" , size = 3,  alpha = 0.5, inherit.aes = FALSE) +
 # coord_sf(datum = sf::st_crs(4326)) +
  labs(title = "Albany Sinking",
       x = NULL,
       y = NULL) +
   theme_bw()

enter image description here

r ggmap sf
1个回答
1
投票

如果将geom_point()与lon和lat分别用作x和y,则该方法有效。

df <- tibble(lon,lat) %>% st_as_sf( coords = c("lon", "lat"), crs = 4326,
                                    remove = FALSE)

ggmap_aus + 
  geom_point(data = df, colour = "red", size = 3,  alpha = 0.5,
             aes(x = lon, y = lat)) +
  # coord_sf(datum = sf::st_crs(4326)) +
  labs(title = "Albany is saved",
       x = NULL,
       y = NULL) +
  theme_bw()

enter image description here

基于this comment,将geom_point()与x和y美学结合使用,与ggmap如何生成ggplot更加紧密地对齐。

[不幸的是,我不确定如何使它与geom_sf()一起使用,后者使用geometry列进行绘制。该链接的注释中有一些讨论,但是解决方案似乎是使用您已经尝试过的inherit.aes = FALSE

基于警告Coordinate system already present. Adding new coordinate system, which will replace the existing one.,我认为ggmap对象的坐标系不是4326,但是我找不到如何访问它的坐标系。我确实尝试将df重新投影到EPSG:3857,但这没有用。

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