我试图从猫库traverse
使用sequence
(或https://typelevel.org/cats/typeclasses/traverse.html,这与我的任务几乎相同)。我想用函数List[A]
遍历A => Either[L,R]
以获得Either[L,List[R]]
。
考虑以下微小的例子(我使用scala-2.12.6,cats-core-1.3.1,sbt-1.1.2):
import cats.implicits._
def isOdd(i: Int): Either[String, Int] =
if (i % 2 != 0) Right(i) else Left("EVEN")
val odd: Either[String, List[Int]] = (1 to 10).toList.traverse(isOdd)
它不编译,它给出:
no type parameters for method traverse: (f: Int => G[B])(implicit evidence$1: cats.Applicative[G])G[List[B]] exist so that it can be applied to arguments (Int => Either[String,Int])
[error] --- because ---
[error] argument expression's type is not compatible with formal parameter type;
[error] found : Int => Either[String,Int]
[error] required: Int => ?G[?B]
[error] val odd: Either[String, List[Int]] = (1 to 10).toList.traverse(isOdd)
type mismatch;
[error] found : Int => Either[String,Int]
[error] required: Int => G[B]
[error] val odd: Either[String, List[Int]] = (1 to 10).toList.traverse(isOdd)
[error] ^
could not find implicit value for evidence parameter of type cats.Applicative[G]
[error] val odd: Either[String, List[Int]] = (1 to 10).toList.traverse(isOdd)
[error] ^
部分统一编译器标志是必需的。在scala 2.12中
在scalacOptions += "-Ypartial-unification"
添加build.sbt
谢谢托马斯