TSQL;提示表的棘手连接。每个Cust_ID

Question

您能否帮助您确定生成输出表的方式，如下图所示。这是我需要的成员资格/差距棘手处理的一部分。无法弄清楚如何为每个提示日期输入EACH Cust_ID。谢谢

示例代码：（*最后选择需要改进）]

CREATE TABLE #test (Cust_ID Varchar(14), Contr_ID INT, ENR_START date, ENR_END date)
INSERT INTO #test values (1, 1, '2018-1-2',  '2018-01-5'),  (1, 2, '2018-01-7', '2018-1-8'),
                         (2, 1, '2018-01-6', '2019-1-10')      ----- select * from  #test

 select top (DATEDIFF(DAY, @Period_Start, @Period_End + 1))    ----- create tally
            DATEADD(dd,ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1,@Period_Start)  dt 
            into #c                             --   select * from #c   -- 10 days
 from master..spt_values  


SELECT    t.*, c.dt 
FROM   #c  c   
left JOIN   #test t      on c.dt  between t.ENR_START  and t.ENR_END 
 order by 1, 5

Answer 1

我认为这是您想要的逻辑：

select cu.cust_id, c.dt, t.*
from (select distinct cust_id from test) cu join
     c
     on c.dt between '2018-01-01' and '2018-01-10' left join
     test t
     on t.cust_id = cu.cust_id and c.dt between enr_start and enr_end
order by cu.cust_id, c.dt;

想法是生成所有cust_id /日期组合，然后将left join转换为原始数据以获取任何匹配项。

Here是db <>小提琴。