onSuccess的值不是scala.concurrent.Future [Any]

Question

我想从URL发出请求，但无法执行

          val f: Future[Any] = actor1 ? SyncRequest(url)
            f.onSuccess {
              case feed: xml.Elem => 
                val feedInfo = FeedInfo(
                        ((feed \ "channel") \ "title").headOption.map(_.text).get,
                        ((feed \ "channel") \ "description").headOption.map(_.text),
                        ((feed \ "channel") \\ "item").map(item =>
                          FeedItem((item \ "title").headOption.map(_.text).get,
                                    (item \ "link").headOption.map(_.text))
                        ).toList
                      )

                complete(feedInfo)

这是错误：

[错误]值onSuccess不是scala.concurrent.Future [Any]]的成员>

[[错误] f.onSuccess {

[错误] ^

[[错误]发现一个错误

[错误]（编译/ compileIncremental）编译失败

也许我必须使用OnComplete之类的东西而不是OnSuccess有人可以帮忙!! ??

我想从某个网址发出请求，但无法通过val f：Future [Any] = actor1吗？ SyncRequest（url）f.onSuccess {案例供稿：xml.Elem => ...

Answer 1

onSuccess方法在Scala 2.12中已弃用，在scala 2.13中已删除]