组成员之间的拆分计数

Question

我有一个如下所示的SQL结果：

+-----------+------------+
| AGENTCODE |  DEAL_ID   |
+-----------+------------+
|    110434 | SO20001353 |
|    108415 | SO20001344 |
|    106188 | SO20001344 |
|    107689 | SO20001342 |
|    109150 | SO20001340 |
|    109150 | SO20001341 |
+-----------+------------+

[如果我按代理商代码分组并计算deal_id，则每个代理商获得的交易数量，从我的逻辑上来说，如果一笔交易中有一个以上的代理商，那么每个交易应获得1个代理商。这是SQL的选项，还是我需要为此编写程序？

我想要的结果看起来像这样：

+-----------+-------+
| AGENTCODE | DELAS |
+-----------+-------+
|    110434 |     1 |
|    108415 |   0.5 |
|    106188 |   0.5 |
|    107689 |     1 |
|    109150 |     2 |
+-----------+-------+

谢谢。

当前代码

SELECT d.AGENTCODE,
       SUM(c.DEAL_COUNT) AS DEALS
FROM (
         SELECT AGENTS.AGENTCODE,
                ORDERS.ORD
         FROM AGENTS,
              BRANCHES,
              CPROFTYPES,
              ORDERS,
              ORDSTATUS,
              ORDERITEMS,
              TRANSPAYMENT,
              TRANSORDER
         WHERE ORDERITEMS.EPI_AGENT = AGENTS.AGENT
           AND ORDERITEMS.PART = 25 /*5003*/
           AND ORDERS.ORD = ORDERITEMS.ORD
           AND ORDERS.BRANCH = BRANCHES.BRANCH
           AND ORDERS.ORDTYPE = CPROFTYPES.CPROFTYPE
           AND TRANSORDER.EPI_PAYDATE BETWEEN 16830720 AND 16917120
           AND ORDERS.ORDSTATUS = ORDSTATUS.ORDSTATUS
           AND ORDSTATUS.ORDSTATUSDES != 'canceled'
           AND TRANSPAYMENT.ORD = ORDERS.ORD
           AND TRANSPAYMENT.TRANS = TRANSORDER.TRANS
           AND TRANSORDER.EPI_CKPAY = 'Y'
           AND TRANSORDER.TRANS != 0
           AND NOT EXISTS(SELECT 'X'
                          FROM TRANSPAYMENT TRP
                             , TRANSORDER TRS
                          WHERE TRP.ORD = ORDERS.ORD
                            AND TRP.TRANS = TRS.TRANS
                            AND TRS.EPI_PAYDATE
                              > 16917120
                            AND TRS.TRANS != 0)
           AND CPROFTYPES.TYPECODE IN ('21', '22', '26', '29')
     ) AS d
         CROSS APPLY (SELECT 1.00 / COUNT(*) AS DEAL_COUNT FROM ORDERS WHERE ORD = d.ORD) c
GROUP BY d.AGENTCODE
ORDER BY d.AGENTCODE;

Answer 1

一种可能的方法：

表格：

CREATE TABLE Data (
    AGENTCODE int,
    DEAL_ID varchar(10)
)
INSERT INTO Data
    (AGENTCODE, DEAL_ID)
VALUES
    (110434, 'SO20001353'),
    (108415, 'SO20001344'),
    (106188, 'SO20001344'),
    (107689, 'SO20001342'),
    (109150, 'SO20001340'),
    (109150, 'SO20001341')

声明：

SELECT d.AGENTCODE, SUM(c.DEAL_COUNT) AS DEAL_COUNT
FROM Data d
CROSS APPLY (SELECT 1.00 / COUNT(*) AS DEAL_COUNT FROM Data WHERE DEAL_ID = d.DEAL_ID) c
GROUP BY d.AGENTCODE
ORDER BY d.AGENTCODE

结果：

AGENTCODE  DEAL_COUNT
106188     0.5000000000000
107689     1.0000000000000
108415     0.5000000000000
109150     2.0000000000000
110434     1.0000000000000

声明，根据您更新的问题：

SELECT d.AGENTCODE, SUM(c.DEAL_COUNT) AS DEAL_COUNT
FROM (
   SELECT *
   FROM AGENTS,
      BRANCHES,
      CPROFTYPES,
      ORDERS,
      ORDSTATUS,
      ORDERITEMS,
      TRANSPAYMENT,
      TRANSORDER
   WHERE 
      ORDERITEMS.EPI_AGENT = AGENTS.AGENT
      AND ORDERITEMS.PART = 25 /*5003*/ 
   ...
) d
CROSS APPLY (SELECT 1.00 / COUNT(*) AS DEAL_COUNT FROM Data WHERE DEAL_ID = d.DEAL_ID) c
GROUP BY d.AGENTCODE
ORDER BY d.AGENTCODE

Answer 2

  select AGENTCODE,   
     COUNT(AGENTCODE ) OVER (PARTITION  BY  DEAL_ID) * 1.00  / COUNT( DEAL_ID) OVER (PARTITION  BY   AGENTCODE) * 1.00  AS DELAS 
  FROM Data; 

演示：https://rextester.com/ENK8799

结果：

    AGENTCODE   DEAL_ID
1   110434  SO20001353
2   108415  SO20001344
3   106188  SO20001344
4   107689  SO20001342
5   109150  SO20001340
6   109150  SO20001341

    AGENTCODE   DELAS
1   106188  2,000000000000000
2   107689  1,000000000000000
3   108415  2,000000000000000
4   109150  0,500000000000000
5   109150  0,500000000000000
6   110434  1,000000000000000