获得2个元素之间的汤

Question

我有以下HTML代码：

<div class="info">
    <div class="left-wrap"><span class="date">DATE-1</span></div>
</div>

<div class="clients-list">
        <div>
            <span class="client" >client1</span>
            <span class="client" >client2</span>
            <span class="client" >client3</span>
        </div>
    </div>

<div class="info">
    <div class="left-wrap"><span class="date" >DATE-2</span></div>
</div>
<div class="clients-list">
        <div>
            <span class="client" >client4</span>
            <span class="client" >client5</span>
        </div>
</div>

我想获取与每个日期有关的数据，我做了以下工作：

date = []
clients = []
for item in soup.find_all(class_='date'):
    date.append(item.get_text().strip())
for item in soup.find_all(class_='client'): 
    clients.append(item.get_text().strip())
print date
print clients

我最终得到包含“ date1”和“ date2”的日期列表，以及包含client1到client5的客户端列表。

我的问题是我无法映射具有date的客户端，例如client1，client2和client3，并且与date1相关，但是我仍然找不到要知道每个日期下有多少个客户端。

Answer 1

您可以使用itertools.groupby：

from bs4 import BeautifulSoup as soup
import itertools as it, re
data = soup(html, 'html.parser').find_all('span', {'class':re.compile('client|date')})
r = [[i.text for i in b] for _, b in it.groupby(data, key=lambda x:x['class'][0] == 'client')]
result = {r[i][0]:r[i+1] for i in range(0, len(r), 2)}

输出：

{'DATE-1': ['client1', 'client2', 'client3'], 'DATE-2': ['client4', 'client5']}