Python 错误：如何打印存储为变量的数字而不将其设为字符串？ [重复]

Question

我正在创建一个练习程序，显示角色的姓名及其年龄。由于某种原因，每当我存储角色的年龄而不用引号引起来时，它就不会打印。

我在视频中看到，将数字存储为变量时，不需要在其周围加上引号。你们可以检查一下我的代码，让我知道我需要更改或添加什么吗？

character_name = "Tyrone"
character_age = 22
print("There was once a man named " + character_name + ",")
print("he was " + character_age + " years old.")
print("He really liked the name " + character_name + ",")
print("but didn't like being " + character_age + ".")

TypeError：只能将 str（不是“int”）连接到 str

Answer 1

解决方案有很多：

• 将数字作为单独的参数传递给

  print()

  -

  print()

  函数可以采用多个参数：

  print("he was", character_age, "years old.")
  

• 使用格式创建一个包含数字的字符串：

  print("he was %s years old." % character_age)
  print("he was {} years old.".format(character_age))
  print(f"he was {character_age} years old.")
  

• 在连接之前将数字转换为字符串：

  print("he was " + str(character_age) + " years old.")
  

Answer 2

最好的方法是在字符串中使用

format()

和符号

{}

。

它也更便携，可以处理各种对象，包括数字和字符串。

而且更清晰了，你的短信完全保留在那里，看看那个！

print("There was once a man named {},".format(character_name))
print("he was {} years old.".format(character_age))
print("He really liked the name {},".format(character_name))
print("but didn't like being {}.".format(character_age))

Answer 3

对于蟒蛇<2.7 and 3 you can use:

#!/bin/env python
character_name = "Tyrone"
character_age = 22
print("There was once a man named " + character_name + ",")
print("he was {0}".format(character_age) + " years old.")
print("He really liked the name " + character_name + ",")
print("but didn't like being {0}".format(character_age) + ".")

对于 python >2.7，您可以排除位置限定符 - {} 而不是 {0} 也可以。