我正在尝试将页面从数据库映射到域的根:
现在我已经有了
/posts/post1-url
/posts/post2-url/slashed
我想要
/post1-url
/post2-url/slashed
我怎样才能使路由器将上面的字符串与db匹配,如果不匹配,则继续匹配下面的routeList?
<?php
public static function createRouter(): RouteList
{
$router = new RouteList;
$router->addRoute('/', 'Home:default');
$router->addRoute('/auth', 'Auth:default');
$router->addRoute('/auth/<action>', 'Auth:<action>');
$router->addRoute('/admin', 'Admin:default');
$router->addRoute('/admin[/<action>][/<slug>]', 'Admin:<action>');
$router->addRoute('/<slug>', 'Home:viewPage');
$router->addRoute('<presenter>/<action>', '<presenter>:<action>');
return $router;
}
我有演示者操作,可以处理显示数据库帖子,但找不到在操作中匹配路由列表的方法,或其他方法来组合匹配+路由列表
我正在使用这种方法。
博客路由器.php
<?php declare(strict_types=1);
namespace App\Router;
use Nette\Http\IRequest;
use Nette\Http\UrlScript;
use Nette\Routing\Router;
use Nette\Utils\Strings;
final class BlogRouter implements Router
{
private const Posts = [
'first-page',
'second/page',
];
public function match(IRequest $httpRequest): ?array
{
$slug = Strings::trim($httpRequest->getUrl()->getPath(), '/');
if (in_array($slug, self::Posts)) {
return [
'presenter' => 'Blog',
'action' => 'post',
'slug' => $slug,
];
}
return null;
}
public function constructUrl(array $params, UrlScript $refUrl): ?string
{
if (!array_key_exists('slug', $params) || !in_array($params['slug'], self::Posts)) {
return null;
}
return $refUrl->getHostUrl() . '/' . $params['slug'] . '/';
}
}
RouterFactory.php
<?php declare(strict_types=1);
namespace App\Router;
use Nette\Application\Routers\RouteList;
use Nette\Routing\Router;
use Nette\StaticClass;
final class RouterFactory
{
use StaticClass;
public static function createRouter(): RouteList
{
$router = new RouteList;
$router->add(new BlogRouter());
$router->addRoute('/<slug [0-9a-z-]+>/', 'Page:default');
$router->addRoute('/', 'Homepage:default');
return $router;
}
}
您只需更新 BlogRouter 代码即可使用数据库。但你应该缓存 uri,而不是在每个请求上查询它们。