假设您有两个表，它们的替换必须保持原样，而另一个表包含一个名称主体。我如何获得所有可能的替代品？
Substitution Table
--------------------------------------
word subs_list
MOUNTAIN MOUNTAIN, MOUNT, MT, MTN
HOUSE HAUS, HOUSE
VIEW VU, VIEW
Synonyms table
-------------------------------------------------
EDUCATION SCHOOL, UNIVERSITY, COLLEGE, TRAINING
FOOD STORE, FOOD, CAFE
STORE FOOD, STORE, MARKET
REFRIGERATION FOODLOCKER, FREEZE, FRIDGE
names table
------------------------------------------------
MOUNT VU FOOD USA
MOUNTAIN VU STORE CA
注意：我知道只需要一个替换表，但是两个替换表都必须保留，因为它们用于除上述目的之外的其他目的，这些表已经被使用了。此外，两个表中的替换列表只是一个varchar，其字符串以逗号分隔
考虑到前面的问题，问题是生成可能通过替换派生的名称。例如，名称MOUNT VU FOOD USA应该分解为MOUNTAIN VIEW FOOD USA和MOUNTAIN VIEW STORE USA，第二种方法将采用相同的方式。
我已经能够以错误的顺序获得替换品，并且全部起作用，有一种方法获得替换后生成的具有不同名称的输出数组？到目前为止，我已经创建了该函数进行替换：
create or replace function replace_companies_array(i_sentence IN VARCHAR) returns VARCHAR[] AS $p_replaced$
DECLARE
p_replaced VARCHAR[];
subs RECORD;
flag boolean:= True;
cur_s CURSOR(i_sentence VARCHAR)
FOR SELECT w.input, coalesce(x.word, w.input) as word, count(*) OVER (PARTITION BY w.input) as counter
FROM regexp_split_to_table(trim(i_sentence), '\s') as w(input)
LEFT JOIN (
select s.word, trim(s1.token) as token
from subs01 s
cross join unnest(string_to_array(s.subs_list, ',')) s1(token)
union
select sy.word, trim(s2.token) as token
from syns01 sy
cross join unnest(string_to_array(sy.syn_list, ',')) s2(token)
) as x on lower(trim(w.input)) = lower(x.token)
order by counter;
BEGIN
OPEN cur_s(i_sentence);
LOOP
--fetch row into the substitutions
FETCH cur_s INTO subs;
--Exit when no more rows to fetch
EXIT WHEN NOT FOUND;
SELECT REGEXP_REPLACE(i_sentence,'(^|[^a-z0-9])' || subs.input || '($|[^a-z0-9])','\1' || UPPER(subs.word) || '\2','g')
INTO i_sentence;
END LOOP;
p_replaced:=array_append(p_replaced, i_sentence);
RETURN p_replaced;
END;
$p_replaced$ LANGUAGE plpgsql;
非常感谢您的贡献
我没有得到最终结果，但是我很接近它！
从句子：MOUNT VU FOOD USA，我得到{"MOUNTAIN VIEW MARKET USA","MOUNTAIN VIEW STORE USA","MOUNTAIN VIEW CAFE USA","MOUNTAIN VIEW FOOD USA"}
这里是我所有用来重新创建同义词和替代表的脚本：
DROP TABLE IF EXISTS subs01;
DROP TABLE IF EXISTS syns01;
CREATE TABLE subs01 (word VARCHAR(20), subs_list VARCHAR(200));
CREATE TABLE syns01 (word VARCHAR(20), syn_list VARCHAR(200));
INSERT INTO subs01 (word, subs_list) VALUES ('MOUNTAIN', 'MOUNTAIN, MOUNT, MT, MTN'),('HOUSE', 'HAUS, HOUSE'),('VIEW', 'VU, VIEW');
INSERT INTO syns01 (word, syn_list) VALUES ('EDUCATION', 'SCHOOL, UNIVERSITY, COLLEGE, TRAINING'),('FOOD', 'STORE, FOOD, CAFE'),('STORE', 'FOOD, STORE, MARKET'),('REFRIGERATION', 'FOODLOCKER, FREEZE, FRIDGE');
我决定将工作分为两个阶段：
替换单词：
CREATE OR REPLACE function substitute_words (i_sentence IN VARCHAR) returns VARCHAR AS $p_substituted$
DECLARE
--p_substituted VARCHAR;
subs_cursor CURSOR FOR select su.word, trim(s2.token) as token from subs01 su cross join unnest(string_to_array(su.subs_list, ',')) s2(token);
subs_record record;
BEGIN
OPEN subs_cursor;
LOOP
FETCH subs_cursor INTO subs_record;
EXIT WHEN NOT FOUND;
RAISE NOTICE 'INFO : TOKEN (%) ',subs_record.token ;
IF i_sentence LIKE '%'|| subs_record.token || '%' THEN
RAISE NOTICE '-- FOUND : TOKEN (%) ',subs_record.token ;
SELECT replace (i_sentence, subs_record.token, subs_record.word) INTO i_sentence;
END IF;
END LOOP;
CLOSE subs_cursor;
RETURN i_sentence;
END
$p_substituted$ LANGUAGE plpgsql;
用公理代替已知单词：
CREATE OR REPLACE function synonymize_sentence (i_sentence IN VARCHAR) returns TABLE (sentence_result VARCHAR) AS $p_syn$
DECLARE
syn_cursor CURSOR FOR select su.word, trim(s2.token) as token from syns01 su cross join unnest(string_to_array(su.syn_list, ',')) s2(token);
syn_record record;
BEGIN
CREATE TEMPORARY TABLE record_syn (result VARCHAR(200)) ON COMMIT DROP;
INSERT INTO record_syn (result) SELECT i_sentence;
OPEN syn_cursor;
LOOP
FETCH syn_cursor INTO syn_record;
EXIT WHEN NOT FOUND;
RAISE NOTICE 'INFO : WORD (%) ',syn_record.word ;
INSERT INTO record_syn (result) SELECT replace (result, syn_record.word, syn_record.token) FROM record_syn where result LIKE '%'|| syn_record.word || '%';
END LOOP;
CLOSE syn_cursor;
RETURN QUERY SELECT distinct result FROM record_syn;
END;
$p_syn$ LANGUAGE plpgsql;
然后，要生成结果数组，请执行以下语句：
SELECT ARRAY(SELECT synonymize_sentence (substitute_words ('MOUNT VU FOOD USA')));