Django REST框架的嵌套API视图？

Question

目前我开发了以下代码，让我获得每个用户的联系人列表。视图返回用户的联系人的ID号。我需要获取所述联系人的“名称”和“last_name”属性，而不是ID号。我是Django的REST框架的新手，我不太确定下一步该做什么，但我相信我必须嵌套APIView。我真的很感激一些帮助！

views.朋友

def list_contacts(request, id_profile):
    url = request.build_absolute_uri(reverse('api_users:contact_list', kwargs={'pk':id_profile}))
    response = requests.get(url)
    profile = Profile.objects.get(pk=id_profile)
    if response.status_code == status.HTTP_200_OK:
        data = response.content
        user = json.loads(data)
        return render(request, 'profiles/contact_list.html', {'user':user})

models.朋友

class Profile(models.Model):
    id_user = models.OneToOneField(User, on_delete=models.CASCADE)
    name = models.CharField(max_length=50)
    last_name = models.CharField(max_length=50)
    birthday = models.DateField(auto_now=False)
    description = models.CharField(max_length=100)
    profile_picture = models.ImageField(upload_to='images/profiles/%Y/%m/%d', blank=False)
    active = models.BooleanField(default = False)
    contacts = models.ManyToManyField('self', blank=True, default='null')
    created_at = models.DateTimeField(default=timezone.now)
    updated_at = models.DateTimeField(default=timezone.now)
    deleted_at = models.DateTimeField(blank=True, null=True)

    class Meta:
        ordering = ('-id',)

    def __str__(self):
        return self.name+' '+self.last_name

    def active_profiles():
        return Profile.objects.filter(active=True)

API / views.py

class ContactListView(generics.ListAPIView):

queryset = Profile.objects.all()
serializer_class = UserContactListSerializer
filter_backends = (filters.SearchFilter,)
search_fields = ('name', 'last_name',)

def get(self, request, pk, format=None):
    contacts = Profile.objects.get(pk=pk)
    serializer = UserContactListSerializer(contacts)
    return Response(serializer.data)

API / serializers.py

class UserContactListSerializer(serializers.ModelSerializer):

    class Meta:
        model = Profile
        fields = ['name','last_name','contacts']

Answer 1

我不知道你的list_contacts到底发生了什么，但是如果你想要使用相同的序列化器作为一个字段本身，你目前不能。 虽然Django模型允许您使用'self'作为参考，但DRF却没有。

你可以做的是创建另一个序列化程序并将其用作字段。

class UserSerializer(serializers.ModelSerializer):
    class Meta:
        model = Profile
        fields = ("id", "first_name", "last_name")

class UserContactListSerializer(serializers.ModelSerializer):
     contacts = UserSerializer(many=True)

     class Meta:
         model = Profile
         fields = ("id", "first_name", "last_name", "contacts")