任何人都知道如何在sequelize seeder上自定义选择查询
我尝试了两种方法,但没有一种有效
第一次尝试
up: function(queryInterface, Sequelize) {
return queryInterface.sequelize.query(
'SELECT * FROM "Users" WHERE username = "admin"',
{ type: queryInterface.sequelize.QueryTypes.SELECT }
).then(function(users) {});
},
然后出现错误
SequelizeDatabaseError: column "admin" does not exist
我不明白为什么管理员列在这里???
第二次尝试
return queryInterface.sequelize.query('SELECT * FROM "Users" WHERE username = :admin', {
replacement: {
admin: 'admin'
},
type: queryInterface.sequelize.QueryTypes.SELECT
}).then(function(users) {
});
出现以下错误
SequelizeDatabaseError: syntax error at or near ":"
第三次尝试
return queryInterface.sequelize.query(
'SELECT * FROM "Users" WHERE username = ' admin '',
{type: queryInterface.sequelize.QueryTypes.SELECT})
.then(function(users) { })
错误:
SyntaxError: missing ) after argument list
已更新
第四次尝试
return queryInterface.sequelize.query(
'SELECT * FROM Users WHERE username = "admin"',
{ type: queryInterface.sequelize.QueryTypes.SELECT }
).then(function(users) {});
出现另一个错误:
SequelizeDatabaseError: relation "Users" does not exist
queryInterface.sequelize.query('SELECT * FROM "Users"')
工作没有任何错误。我认为这里的问题是 WHERE 查询
这让我发疯:)
感谢您提前提供的任何帮助!
仔细阅读Sequelize文档后,我找到了这个问题的解决方案。 对原始查询替换进行排序。如果您遇到同样的问题,请尝试以下解决方案
return queryInterface.sequelize.query(
'SELECT * FROM "Users" WHERE username = ? ', {
replacements: ['admin'],
type: queryInterface.sequelize.QueryTypes.SELECT
}).then(users => {
关于@Toan Tran 答案,更新您的迁移:
await queryInterface.sequelize.query(`
UPDATE public."Table"
SET "column_to_be_updated" = :column::uuid
WHERE public."Permissions"."column_to_check" = :column_to_check
`, {
replacements: { column_to_be_updated: r.uuid, column_to_check: r.name },
type: Sequelize.QueryTypes.UPDATE
});
这是使用 PostgresSQL 的 Sequelize。请注意,此更新也适用于类型为
column
的 Sequelize.UUID
。