我的python代码跳过了txt文件的第一行?

问题描述 投票:0回答:1

我正在研究这段代码,它从一个.txt文件中复制行并将其用于算法,然后将结果保存到另一个文件中。程序总是跳过第一行,而不是像第一个.txt文件那样输出6行,而是输出5行。我已经研究了很久,但似乎找不到是什么原因。下面是代码。

encryptString = []
counter = 0
dTagID = []
longVer = []
shortVer = []
#reading
fRead = open("certTags.txt", "r")
for line in fRead.readlines():
    dTagID.append(line)
lengthList = len(dTagID)
while counter < lengthList:
    tempSave = encryptSave + dTagID[counter]
    tempSave = int(tempSave)
    # Encryption
    msg = tempSave
    msge = msg**e
    msgn = msge % N
    msgn = str(msgn)
    longVer.append(msgn)
    # Checksum
    checksum = sum(map(int, msgn))
    checksum = str(checksum)
    shortVer.append(encryptSave+checksum)
    # Saving to file
    fWriteS = open("shortVer.txt", "a+")
    fWriteS.write(shortVer[counter] + '\n')
    fWriteL = open("longVer.txt", "a+")
    fWriteL.write(longVer[counter] + '\n')
    counter = counter + 1
python python-3.x list file read-write
1个回答
1
投票

你的代码没有遵循许多最佳实践,这使得它很难理解和调试。下面是我对如何使它更pythonic的看法。

longVer = []
shortVer = []
#reading
with open("certTags.txt", "r") as fRead:
    for line in fRead:
        msg = int(encryptSave + line)
        # Encryption
        msg = str(msg**e % N)
        longVer.append(msg)
        # Checksum
        checksum = str(sum(map(int, msg)))
        shortVer.append(encryptSave + checksum)

# Saving to file
with open("shortVer.txt", "w") as fWriteS:
    fWriteS.write("\n".join(shortVer))
with open("longVer.txt", "w") as fWriteL:
    fWriteL.write("\n".join(longVer))

我不知道什么是... encryptSave 因为你从未定义过这个变量。我认为它是一个字符串。

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