这是我的编码,如下。
import random
import math
def count_hit_in_cirle(iteration):
randX=random.uniform(-1.0,1.0) # returns a X random float in INclusive [-1.0, 1.0]
randY=random.uniform(-1.0,1.0) # returns a y random float in INclusive [-1.0, 1.0]
one_if_in_circle=0
for i in range(iteration):
def one_if_in_circle(randX, randY):
if math.sqrt(randX*randX+randY*randY) <= 1:
return 1
else:
return 0
return (sum(one_if_in_circle(randX, randY)))
count_hit_in_cirle(1000)
但是我遇到这样的错误:
count_hit_in_cirle(1000)
Traceback (most recent call last):
File "<ipython-input-4-4dcc579bc645>", line 1, in <module>
count_hit_in_cirle(1000)
File "<ipython-input-3-4fbc77f1c9ec>", line 11, in count_hit_in_cirle
return (sum(one_if_in_circle(randX, randY)))
TypeError: 'int' object is not iterable
然后我尝试:
return (sum(one_if_in_circle(randX, randY)))
仍然出现错误:
“ TypeError:'函数'对象不可迭代”
有人可以告诉我如何修改编码吗?非常感谢
one_if_in_circle在one_if_in_circle=0
中定义为int类型变量,在def one_if_in_circle(randX, randY)
中定义为函数。更改其中之一。
似乎您正在尝试创建一个生成器。您需要将循环放在函数内部而不是函数周围,并使用yield
而不是return
。
def count_hit_in_cirle(iteration):
randX=random.uniform(-1.0,1.0) # returns a X random float in INclusive [-1.0, 1.0]
randY=random.uniform(-1.0,1.0) # returns a y random float in INclusive [-1.0, 1.0]
one_if_in_circle=0
def one_if_in_circle(randX, randY):
for i in range(iteration):
if math.sqrt(randX*randX+randY*randY) <= 1:
yield 1
else:
yield 0
return (sum(one_if_in_circle(randX, randY)))
您的函数仅返回一个整数,而不是sum()
可以迭代的序列。