对象生成到另一个对象的边界

Question

我使用 ncurses 库和 C++ 创建了一个简单的游戏。主要思想是一个黄色方块的玩家在棋盘上行走并收集尽可能多的“*”。它也不能撞到障碍物和边界。开始时，会生成 100 个，收集完一个后，会在随机位置生成另一个。我的问题是：在生成星号之前，我正在检查障碍物的坐标，以避免星号在障碍物内生成。它在大多数情况下都有效，但在一些非常罕见的情况下，星号会在障碍物内生成。我有任何逻辑错误吗？还是我做错了什么？我的解决方案有什么替代方案？

这些是关于障碍物的数据

    mainwin = initscr();
    obscatle=subwin(mainwin,7,2,1,6);
    obscatle2=subwin(mainwin,10,2,8,20);
    obscatle3=subwin(mainwin,2,2,17,50);
    obscatle4=subwin(mainwin,6,2,25,70);
    obscatle5=subwin(mainwin,12,2,10,90);
    obscatle6=subwin(mainwin,20,2,8,110);
    obscatle7=subwin(mainwin,22,2,4,130);
    obscatle8=subwin(mainwin,17,2,18,150);

这些是函数。

//At the start of the game, spawn asterisks on random positions
vector<pair<int,int>> generate_asterisk(int numberOfLines, int numberOfColumns) {
    vector<pair<int,int>> coordinates;
    srand(time(0)); 
    while(coordinates.size() < 500) {
        int x = (rand() % (COLS - 3)) + 1;
        int y = (rand() % (LINES - 5)) +1;

        // Check if x and y match the given values, and generate new random values until they don't match
        while((y >= 1 && y <= 7 && (x >= 5 && x <= 9)) ||
               (y >= 8 && y <= 17 && (x >= 19 && x <= 23)) ||
               (y >= 17 && y <= 18 && (x >= 49 && x <= 53)) ||
               (y >= 25 && y <= 30 && (x >= 69 && x <= 73)) ||
               (y >= 10 && y <= 21 && (x >= 89 && x <= 93)) ||
               (y >= 8 && y <= 27 && (x >= 109 && x <= 114)) ||
               (y >= 4 && y <= 25 && (x >= 129 && x <= 134)) ||
               (y >= 18 && y <= 34 && (x >= 149 && x <= 154))) {
            x = (rand() % (COLS - 3)) + 1;
            y = (rand() % (LINES - 5)) + 1;
        }

        pair<int,int> coord = make_pair(x,y);
        if(find(coordinates.begin(), coordinates.end(), coord) == coordinates.end()) {
            coordinates.push_back(coord);
        }
    }
    return coordinates;
}



//after collecting, spawn a new one
void spawnAsterisk(WINDOW* win, int x_max, int y_max, std::vector<std::pair<int, int>>& asterisk_coords)
{
    // Generate new coordinates for the asterisk
        int new_x = (rand() % (COLS - 3)) + 1;
        int new_y = (rand() % (LINES - 5)) +1;

        while((new_y >= 1 && new_y <= 7 && (new_x >= 5 && new_x <= 9)) ||
               (new_y >= 8 && new_y <= 17 && (new_x >= 19 && new_x <= 23)) ||
               (new_y >= 17 && new_y <= 18 && (new_x >= 49 && new_x <= 53)) ||
               (new_y >= 25 && new_y <= 30 && (new_x >= 69 && new_x <= 73)) ||
               (new_y >= 10 && new_y <= 21 && (new_x >= 89 && new_x <= 93)) ||
               (new_y >= 8 && new_y <= 27 && (new_x >= 109 && new_x <= 114)) ||
               (new_y >= 4 && new_y <= 25 && (new_x >= 129 && new_x <= 134)) ||
               (new_y >= 18 && new_y <= 34 && (new_x >= 149 && new_x <= 154))) {
            new_x = (rand() % (COLS - 3)) + 1;
            new_y = (rand() % (LINES - 5)) + 1;
        }
    // Check if the new coordinates conflict with existing asterisks
    bool conflict = false;
    for (const auto& coord : asterisk_coords)
    {
        if (coord.first == new_x && coord.second == new_y)
        {
            conflict = true;
            break;
        }
 
         
    }

    // If there's a conflict, generate new coordinates until there's no conflict
    while (conflict)
    {
        new_x = rand() % x_max;
        new_y = rand() % y_max;

        conflict = false;
        for (const auto& coord : asterisk_coords)
        {
            if (coord.first == new_x && coord.second == new_y)
            {
                conflict = true;
                break;
            }
        }
    }

    asterisk_coords.push_back(std::make_pair(new_x, new_y));

    mvwprintw(win, new_y, new_x, "*");
    wrefresh(win);
}

我正在手动检查，因为这是我现在的水平。我试过了，因为它在大部分时间都有效，我想我已经接近答案了。或者也许代码是正确的，但错误是因为屏幕尺寸。