将字母匹配到Jython中列表中的相应数字

Question

我正在开发一个程序，当用户输入名称作为参数时，它会将每个字母与列表中存储的相应数字相匹配。

例如：

def nameNumbers(name):
    alphabetList = ['Aa', 8.17, 'Bb', 1.49, 'Cc', 2.78, 'Dd', 4.25, 
  'Ee', 12.70, 'Ff', 2.23, 'Gg', 2.02, 'Hh', 6.09, 'Ii', 6.97, 
  'Jj', 0.15, 'Kk', 0.77, 'Ll', 4.03, 'Mm', 2.41, 'Nn', 6.75, 
  'Oo', 7.51, 'Pp', 1.93, 'Qq', 0.10, 'Rr', 5.99, 'Ss', 6.33, 
  'Tt', 9.06, 'Uu', 2.76, 'Vv', 0.98, 'Ww', 2.36, 'Xx', 0.15, 
  'Yy', 1.97, 'Zz', 0.07]

因此，如果我要传递“亚当”，它将返回：

8.17
4.25
8.17
2.41

到目前为止，我已经知道了，但是它只返回列表中的一项，并且需要输入准确：

    for letter in name:
     indexOfLetter = alphabetList.index(name)
     letterFrequency = alphabetList[indexOfLetter + 1] 
     print(letterFrequency)

谢谢！

Answer 1

只需稍微更改一下代码

代码

def nameNumbers(name):
  alphabetList = ['Aa', 8.17, 'Bb', 1.49, 'Cc', 2.78, 'Dd', 4.25, 
  'Ee', 12.70, 'Ff', 2.23, 'Gg', 2.02, 'Hh', 6.09, 'Ii', 6.97, 
  'Jj', 0.15, 'Kk', 0.77, 'Ll', 4.03, 'Mm', 2.41, 'Nn', 6.75, 
  'Oo', 7.51, 'Pp', 1.93, 'Qq', 0.10, 'Rr', 5.99, 'Ss', 6.33, 
  'Tt', 9.06, 'Uu', 2.76, 'Vv', 0.98, 'Ww', 2.36, 'Xx', 0.15, 
  'Yy', 1.97, 'Zz', 0.07]

  for letter in name:
     # Since each has upper followed by lower case
     # Use letter.upper() + letter.lower() since you have upper 
     indexOfLetter = alphabetList.index(letter.upper() + letter.lower())
     letterFrequency = alphabetList[indexOfLetter + 1] 
     print(letterFrequency)


nameNumbers("Adam")

输出

8.17
4.25
8.17
2.41

替代

程序应计算数字，并在外部打印程序。

此外，for循环可以用更简洁的列表理解代替。

def nameNumbers(name):
  alphabetList = ['Aa', 8.17, 'Bb', 1.49, 'Cc', 2.78, 'Dd', 4.25, 
  'Ee', 12.70, 'Ff', 2.23, 'Gg', 2.02, 'Hh', 6.09, 'Ii', 6.97, 
  'Jj', 0.15, 'Kk', 0.77, 'Ll', 4.03, 'Mm', 2.41, 'Nn', 6.75, 
  'Oo', 7.51, 'Pp', 1.93, 'Qq', 0.10, 'Rr', 5.99, 'Ss', 6.33, 
  'Tt', 9.06, 'Uu', 2.76, 'Vv', 0.98, 'Ww', 2.36, 'Xx', 0.15, 
  'Yy', 1.97, 'Zz', 0.07]

  indexes = [alphabetList.index(letter.upper() + letter.lower()) for letter in name]
  return [alphabetList[i+1] for i in indexes]

print(*nameNumbers("Adam"), sep="\n")

与上述输出相同。