我刚开始在这里的地图看REST API。我已经有了一个C#/。NET编程经验,但不是很多与访问REST的API。我已经设法成功地调用HERE地图的WebService,并已获取的JSON数据,但我试图找出取回我从这个数据所需的特定信息的最佳途径。我想我需要使用Deserialisation,但这似乎需要建立一个适当的C#对象的脱serialse成。我希望有一个仓库的地方在那里我能找到这些对象,而不是将它们从无到有工作了,但不能发现任何东西。任何建议感激地接受。
谢谢,
克里斯。
JSON响应:
{
"Response":{
"MetaInfo":{
"Timestamp":"2019-02-03T20:41:00.395+0000"
},
"View":[
{
"_type":"SearchResultsViewType",
"ViewId":0,
"Result":[
{
"Relevance":1.0,
"MatchLevel":"postalCode",
"MatchQuality":{
"PostalCode":1.0
},
"Location":{
"LocationId":"NT_CwZliV687TLYW4ZZKm4VNA",
"LocationType":"point",
"DisplayPosition":{
"Latitude":50.8082,
"Longitude":-0.39127
},
"NavigationPosition":[
{
"Latitude":50.8082,
"Longitude":-0.39127
}
],
"MapView":{
"TopLeft":{
"Latitude":50.82169,
"Longitude":-0.41262
},
"BottomRight":{
"Latitude":50.79471,
"Longitude":-0.36992
}
},
"Address":{
"Label":"BN11 3PQ, Worthing, England, United Kingdom",
"Country":"GBR",
"State":"England",
"County":"West Sussex",
"City":"Worthing",
"PostalCode":"BN11 3PQ",
"AdditionalData":[
{
"value":"United Kingdom",
"key":"CountryName"
},
{
"value":"England",
"key":"StateName"
},
{
"value":"West Sussex",
"key":"CountyName"
}
]
}
}
}
]
}
]
}
}
您可以选择JSON和粘贴Visual Studio: Edit -> Paste Special -> Paste JSON as classes
C#类。
然后NuGet包Newtonsoft.Json添加到解决方案和反序列化JSON反对,它会寻找为:
using Newtonsoft.Json;
using System;
namespace ConsoleApp1
{
class Program
{
static void Main(string[] args)
{
string json = "";//download json
Rootobject obj = JsonConvert.DeserializeObject<Rootobject>(json);
DateTime tt = obj.Response.MetaInfo.Timestamp;
}
}
public class Rootobject
{
public Response Response { get; set; }
}
public class Response
{
public Metainfo MetaInfo { get; set; }
public View[] View { get; set; }
}
public class Metainfo
{
public DateTime Timestamp { get; set; }
}
public class View
{
public string _type { get; set; }
public int ViewId { get; set; }
public Result[] Result { get; set; }
}
public class Result
{
public float Relevance { get; set; }
public string MatchLevel { get; set; }
public Matchquality MatchQuality { get; set; }
public Location Location { get; set; }
}
public class Matchquality
{
public float PostalCode { get; set; }
}
public class Location
{
public string LocationId { get; set; }
public string LocationType { get; set; }
public Displayposition DisplayPosition { get; set; }
public Navigationposition[] NavigationPosition { get; set; }
public Mapview MapView { get; set; }
public Address Address { get; set; }
}
public class Displayposition
{
public float Latitude { get; set; }
public float Longitude { get; set; }
}
public class Mapview
{
public Topleft TopLeft { get; set; }
public Bottomright BottomRight { get; set; }
}
public class Topleft
{
public float Latitude { get; set; }
public float Longitude { get; set; }
}
public class Bottomright
{
public float Latitude { get; set; }
public float Longitude { get; set; }
}
public class Address
{
public string Label { get; set; }
public string Country { get; set; }
public string State { get; set; }
public string County { get; set; }
public string City { get; set; }
public string PostalCode { get; set; }
public Additionaldata[] AdditionalData { get; set; }
}
public class Additionaldata
{
public string value { get; set; }
public string key { get; set; }
}
public class Navigationposition
{
public float Latitude { get; set; }
public float Longitude { get; set; }
}
}
非常感谢所有的评论。您的建议已经提交,以备将来参考。最后,因为我只需要访问一对夫妇的信息,整个转换为对象bitseemed有点大材小用,所以我得到的结果以XML代替,并用一对夫妇的XML方法(的getElementsByTagName和的childNodes)提取我想要的节点。但是,再次感谢您的建议,我敢肯定,我会使用至少其中一些在未来:)
克里斯。