我想自定义超媒体 Rest JPA 实体的响应,并希望删除所有 _links 属性和自链接属性。 我的客户端应用程序不是那么大,它知道要调用哪些确切的 REST API。因此,我觉得 HTTP 数据包中传输的这些额外字节始终是我的应用程序的开销。
那么我怎样才能从响应中删除这个链接属性呢?
现在 REST API 响应是:
{
"_embedded" : {
"questionsTypes" : [ {
"queTypeID" : 2,
"queDescription" : "Single choice rating selection",
"_links" : {
"self" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType/2"
},
"questionsType" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType/2{?projection}",
"templated" : true
}
}
},{
"queTypeID" : 5,
"queDescription" : "Subjective questions",
"_links" : {
"self" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType/5"
},
"questionsType" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType/5{?projection}",
"templated" : true
}
}
} ]
},
"_links" : {
"self" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType"
},
"profile" : {
"href" : "http://localhost:8080/question_web/rest/profile/QuestionsType"
},
"search" : {
"href" : "http://localhost:8080/question_web/rest/QuestionsType/search"
}
}
}
我期望的最终答复是这样的:
{
"_embedded" : {
"questionsTypes" : [ {
"queTypeID" : 2,
"queDescription" : "Single choice rating selection",
},{
"queTypeID" : 5,
"queDescription" : "Subjective questions",
} ]
}
}
@Component
public class MyEntityProcessor implements RepresentationModelProcessor<EntityModel<MyEntity>> {
@Override
public EntityModel<MyEntity> process(EntityModel<MyEntity> model) {
return EntityModel.of(model.getContent());
}
}
从所有对象中删除所有 _links:
但是这个方法会覆盖任何其他处理器
@Component
public class ObjectRepresentationModelProcessor implements RepresentationModelProcessor<EntityModel<Object>> {
@NonNull
@Override
public EntityModel<Object> process(EntityModel<Object> model) {
return EntityModel.of(model.getContent());
}
}