我有一个从HTTP_HOST返回干净域的代码
preg_replace('#^(.*\.)?(.*\..*)$#', '$2', $_SERVER['HTTP_HOST'])
但是如果域名类似于somedomain.co.uk,则仅返回co.uk。在这种情况下,您能否帮助我重新制作RegExp以返回正确的域?非常感谢!
您应该尝试此:
preg_replace('#^(https?:\/\/)?(www\d?\.)?([^\/\?]+)(.*)#', '$3', $url)
在以下情况下适用:
<?php
$urls = [
'https://www.somedomain.co.uk',
'http://www.somedomain.co.uk',
'www.somedomain.co.uk/something',
'www.somedomain.co.uk?q=1',
'www2.somedomain.co.uk/something',
'somedomain.co.uk',
'192.168.1.1/something?q=1&x=2',
];
foreach($urls as $url) {
echo preg_replace('#^(https?:\/\/)?(www\d?\.)?([^\/\?]+)(.*)#', '$3', $url) . '<br>';
}