flask celery 抛出错误“url 必须以前导斜杠开头”

问题描述 投票:0回答:1

我正在尝试使用 flask 来实现 celery ,当我运行此命令

celery -A src.celery_worker.celery_app worker --loglevel=debug
来启动 celery 工作程序时,它会抛出错误:

无法导入“src.celery_worker.celery_app”:网址必须以 前导斜杠

这是完整的回溯:

Traceback (most recent call last):
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/celery/bin/celery.py", line 58, in convert
    return find_app(value)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/celery/app/utils.py", line 383, in find_app
    sym = symbol_by_name(app, imp=imp)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/kombu/utils/imports.py", line 61, in symbol_by_name
    reraise(ValueError,
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/kombu/exceptions.py", line 34, in reraise
    raise value.with_traceback(tb)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/kombu/utils/imports.py", line 59, in symbol_by_name
    module = imp(module_name, package=package, **kwargs)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/celery/utils/imports.py", line 109, in import_from_cwd
    return imp(module, package=package)
  File "/usr/lib/python3.8/importlib/__init__.py", line 127, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 1014, in _gcd_import
  File "<frozen importlib._bootstrap>", line 991, in _find_and_load
  File "<frozen importlib._bootstrap>", line 961, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
  File "<frozen importlib._bootstrap>", line 1014, in _gcd_import
  File "<frozen importlib._bootstrap>", line 991, in _find_and_load
  File "<frozen importlib._bootstrap>", line 975, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 671, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 848, in exec_module
  File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/src/__init__.py", line 42, in <module>
    api = Api(
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask_restx/api.py", line 197, in __init__
    self.init_app(app)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask_restx/api.py", line 236, in init_app
    self._init_app(app)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask_restx/api.py", line 247, in _init_app
    self._register_doc(self.blueprint or app)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask_restx/api.py", line 320, in _register_doc
    app_or_blueprint.add_url_rule(self._doc, "doc", self.render_doc)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask/scaffold.py", line 56, in wrapper_func
    return f(self, *args, **kwargs)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/flask/app.py", line 1083, in add_url_rule
    rule = self.url_rule_class(rule, methods=methods, **options)
  File "/home/sonnc/project/mac/lifescience-operator-management-bff/venv/lib/python3.8/site-packages/werkzeug/routing.py", line 698, in __init__
    raise ValueError("urls must start with a leading slash")
ValueError: Couldn't import 'src.celery_worker.celery_app': urls must start with a leading slash

以下是文件

src/celery_worker/__init__.py
:

import os
from flask import Flask

from celery import Celery, Task


def celery_init_app(app: Flask) -> Celery:
    class FlaskTask(Task):
        def __call__(self, *args: object, **kwargs: object) -> object:
            with app.app_context():
                return self.run(*args, **kwargs)

    celery_app = Celery(app.name, task_cls=FlaskTask)
    celery_app.config_from_object(app.config["CELERY"])
    celery_app.set_default()
    app.extensions["celery"] = celery_app
    return celery_app


def create_app() -> Flask:
    app = Flask(__name__)
    # url for local redis
    # redis_url = "redis://localhost:6379"
    # url for docker redis
    # redis_url = "redis://redis:6379/0"
    app.config.from_mapping(
        CELERY=dict(
            broker_url="redis://localhost:6379",
            result_backend="redis://localhost:6379",
            task_ignore_result=True,
            # import the tasks
            # imports=("src.common.send_email",),
        ),
    )
    app.config.from_prefixed_env()
    celery_init_app(app)
    return app


flask_app = create_app()
celery_app = flask_app.extensions["celery"]

看起来该错误与

flask_restx
模块有关,但我无法追踪它是如何导致此问题的。
请帮忙,谢谢。


编辑1: 这是我源代码中的每个

route
path
都以斜线开头的证明:

python flask celery flask-restx
1个回答
0
投票

这是错误:

ValueError:无法导入“src.celery_worker.celery_app”:网址必须以前导斜杠开头

这告诉您,您需要在路线前面添加一个前导斜杠

/
,导致
/yourroute

确保所有路线都以斜杠开头,例如

@app.route('/foo/bar/')
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