我需要使该行在我的主要功能board1[{1,1}]='X';
中起作用。我不知道如何使它工作。我想得到一些帮助。这是我的董事会课程:
class Board {
private:
int size;
char** matrix = nullptr;
public:
Board(int sizeToSet) { //constructor with size
size = sizeToSet;
matrix = new char*[size]; //creates a matrix
for (int i = 0; i < size; i++)
matrix[i] = new char[size];
for (int i = 0; i < size; i++) { //makes every cell in matix '.'
for (int j = 0; j < size; j++) {
matrix[i][j] = '.';
}
}
}
void printSize() { //matrix size print
cout << size << endl;
}
~Board() { //destructor
for (int i = 0; i < size; i++)
delete[] matrix[i];
delete[] matrix;
}
Board(const Board& other) { //copy constructor
size = other.size;
matrix = new char*[size];
for (int i = 0; i < size; i++)
matrix[i] = new char[size];
for (int i = 0; i < size; i++) {
for (int j = 0; j < size; j++) {
matrix[i][j] = other.matrix[i][j];
}
}
}
friend ostream& operator<<(ostream& os, const Board& boardToPrint) { //prints matrix
for (int i = 0; i < boardToPrint.size; i++) {
for (int j = 0; j < boardToPrint.size; j++) {
os << boardToPrint.matrix[i][j] << " ";
}
os << endl;
}
return os;
}
int operator()(int row, int col) {
cout << "it worked1" << endl;
return 1;
}
};
重载索引运算符以获取合适的对:
char& operator[](const std::pair<int, int>& xy)
{
return matrix[xy.first][xy.second];
}
您想要做的是用成对或类似符号重载operator[]
char & operator[]( const std::pair<size_t, size_t> &pair ) {
return matrix[pair.first, pair.second]
}