我的代码使用txt文件,并发送电子邮件到列表中的第一封电子邮件,然后停止并为下一个不这样做。什么是我错了这阵在做什么?
我曾尝试创建一个数组运行在target_email
每封电子邮件的功能,而且只发送电子邮件到第一封电子邮件在数组中。当我打印阵列它看起来像这样[[email protected], [email protected]]
####the py script
import time
import smtplib
#CONFIG. You can change any of the values on the right.
email_provider = '' #server for your email- see ReadMe on github
email_address = "" #your email
email_port = 587 #port for email server- see ReadMe on github
password = "" #your email password
msg = "Meow" #your txt message
text_amount = 1 #amount sent
#Gets phone number emails from txt file
text_file = open("mails.txt", "r")
target_email = text_file.readlines()
wait = 15 #seconds in between messages
#END CONFIG
#Loops for each phone email in list text_amount of times
for emails in target_email:
server = smtplib.SMTP(email_provider, email_port)
server.starttls()
server.login(email_address, password)
for _ in range(0,text_amount):
server.sendmail(email_address,target_email,msg)
print("sent")
time.sleep(wait)
print("{} texts were sent.".format(text_amount))
###the txt file contents
[email protected], [email protected]
该脚本应单独和不运行的每封电子邮件的### DO NOT EDIT BELOW THIS LINE ###
一个BBC或只需发送一个电子邮件和停止。
相反,发送个人电子邮件地址,你是送的完整列表。
采用:
#Loops for each phone email in list text_amount of times
for emails in target_email:
### DO NOT EDIT BELOW THIS LINE ###
server = smtplib.SMTP(email_provider, email_port)
server.starttls()
server.login(email_address, password)
for _ in range(0,text_amount):
server.sendmail(email_address,emails,msg) #Update!!
print("sent")
time.sleep(wait)
print("{} texts were sent.".format(text_amount))
编辑按评论。
server = smtplib.SMTP(email_provider, email_port)
server.starttls()
server.login(email_address, password)
with open("mails.txt") as infile:
for line in infile:
line = line.strip()
if "," in line:
emails = line.split(",")
else:
emails = line
for _ in range(0,text_amount):
server.sendmail(email_address,emails,msg)
print("sent")
time.sleep(wait)
print("{} texts were sent.".format(text_amount))