这是我的榜样。
public class Company {
....
private String companyName;
....
}
public class Employee {
....
private String name;
....
}
public class EmployeeDto {
....
private String name;
private String companyName;
....
}
@Mapper(componentModel = "spring")
public interface EmployeeDtoMapper {
@Mapping(target = "name", source = "source1.name")
@Mapping(target = "companyName", source = "source2.companyName")
EmployeeDto toDto(Employee source1, Company source2);
List<EmployeeDto> toDtos(List<Employee> sources, @Context Company source2);
}
我希望方法toDtos使用toDto将Employee映射到EmployeeDto,但mapstruct生成employeeDtoToEmployeeDto方法。我该如何解决?
谢谢
Mapstruct仅允许基于1个源和1个目标选择子映射。因此@Context注释。这将有效地忽略该参数,只将其传递给子映射。
但是......你可以像这样解决你的问题..
@Mapper(componentModel = "spring")
public interface EmployeeDtoMapper {
@Mapping(target = "name", source = "source1.name")
EmployeeDto toDto(Employee source1, @Context Company source2);
@AfterMapping
default afterToDto(@MappingTarget EmployeeDto target, @Context Company source2) {
target.setCompanyName( source2.getCompanyName();
}
List<EmployeeDto> toDtos(List<Employee> sources, @Context Company source2);
}
请注意,如果映射source2中有多个参数,并且您也希望使用MapStruct,则可以定义映射EmployDTO toDo(Company source)
的新接口方法,并从默认方法中调用它。