我如何获得一个提示函数，如果为null并在另一个条件下重复，则返回

Question

我希望该功能在用户单击取消时停止，如果他们输入的数字不符合条件，则重新运行提示。现在，如果我输入的数字不符合条件，它将停止功能。这是怎么了？谢谢！

function findPasswordLength() {

    passwordLength = prompt("Choose character length \n(at least 8 and no more than 128)");

    if (passwordLength >= 8 && passwordLength <= 128) {
        alert("Your password will be " + passwordLength + " characters long");
    }

    else if (passWordLength === null) {
        return;
    }

    else if (typeof(passwordLength) !== "number" || passwordLength < 8 || passwordLength > 128) {
        findPasswordLength();
    }
}

Answer 1

您只是在变量名passwordLength上有错字。

此

else if (passWordLength === null) {

实际上应该是

else if (passwordLength === null) {