我正在使用具有无限滚动的select2组选项,并且数据是通过Ajax调用每页10来的。这里出现了一些问题,假设用户1有15个数据而用户2有15个数据,前10个数据来自用户1和下一页10(user1的5个数据和user2的5个数据)。数据获取没问题,但问题是用户1组显示双倍。如何防止双重显示到我的select2选项组?有没有办法再次组建一个选项组?
HTML代码
<div class="container">
<form id="frm">
<h1>Solution 1</h1>
<div class="row">
<div class="col-4">
<div class="form-group">
<label for="tagInput">Get data by ajax calling</label>
<select class="form-control" id="pictures_tag_input">
</select>
<small class="form-text text-muted"><p class="text-info">Infinite Scroll</p></small>
</div>
</div>
</div>
</form>
</div>
JS代码
$(document).ready(function() {
// solution 1
//example.com/articles?page[number]=3&page[size]=1
http: $("#pictures_tag_input").select2({
placeholder: "Search for options",
ajax: {
url: "https://jsonplaceholder.typicode.com/users/1/todos",
dataType: "json",
global: false,
cache: true,
delay: 250,
minimumInputLength: 2,
data: function(params) {
// console.log(params.page || 1);
return {
q: params.term, // search term
_page: params.page || 1,
_limit: 10 // page size
};
},
processResults: function(data, params) {
params.page = params.page || 1;
var datx = getNestedChildren(data);
// console.log(datx);
return {
results: datx,
pagination: {
more: true
}
};
} //end of process results
} // end of ajax
});
function getNestedChildren(list) {
var roots = [];
for (i = 0; i < list.length; i += 1) {
node = list[i];
if (roots.length === 0) {
var obj = {
text: "User " + node.userId,
children: [{ id: node.id, text: node.title }]
};
roots.push(obj);
} else {
var obj = {
text: "User " + node.userId,
children: [{ id: node.id, text: node.title }]
};
var rootArray = $.map(roots, function(val, i) {
var vl = "User " + node.userId;
if (val.text === vl) return val;
else return undefined;
});
if (rootArray.length > 0) {
var obj1 = {
id: node.id,
text: node.title
};
rootArray[0].children.push(obj1);
} else {
roots.push(obj);
}
}
}
return roots;
}
});
只是尝试使用以下代码
templateResult: function(data) {
if (typeof data.children != 'undefined') {
$(".select2-results__group").each(function() {
if (data.text == $(this).text()) {
return data.text = '';
}
});
}
return data.text;
}
注意:需要从服务器端进行分组,否则您必须从客户端制作主要详细信息。
也许问题是数据的来源
你打电话给用户1 ....服务器返回1
你打电话给用户2 ....服务器返回1
你打电话给用户3 ....服务器返回2
你打电话给用户4 ....服务器返回2
你打电话给用户5 ....服务器返回3
你打电话给用户6 ....服务器返回3
curent_user = 1;
$(document).ready(function() {
http: $("#pictures_tag_input").select2({
placeholder: "Search for options",
ajax: {
url: "https://jsonplaceholder.typicode.com/users/1/todos",
dataType: "json",
global: false,
cache: false,
minimumInputLength: 2,
data: function(params) {
console.log("params",params || 1);
return {
q: params.term, // search term
_page: curent_user,
_limit: 10 // page size
};
},
processResults: function(data, params) {
curent_user += 2;
var datx = getNestedChildren(data);
console.log("data: ", data);
return {
results: datx,
pagination: {
more: true
}
};
} //end of process results
} // end of ajax
});
function getNestedChildren(list) {
var roots = [];
for (i = 0; i < list.length; i += 1) {
node = list[i];
if (roots.length === 0) {
var obj = {
text: "User " + node.userId,
children: [{ id: node.id, text: node.title }]
};
roots.push(obj);
} else {
var obj = {
text: "User " + node.userId,
children: [{ id: node.id, text: node.title }]
};
var rootArray = $.map(roots, function(val, i) {
var vl = "User " + node.userId;
if (val.text === vl) return val;
else return undefined;
});
if (rootArray.length > 0) {
var obj1 = {
id: node.id,
text: node.title
};
rootArray[0].children.push(obj1);
} else {
roots.push(obj);
}
}
}
return roots;
}
});
所以,如果你跳过一步
你打电话给用户1 ....服务器返回1
你打电话给用户3 ....服务器返回2
你打电话给用户5 ....服务器返回3