带有另一个类的List的JSON类

Question

我会尽力解释这个问题。我有一个名为Prospect的类，其中包含电子邮件，公司，名字，姓氏，电话的字符串。

我要求以JSON格式输出JSON中的Prospect信息

[
   {"email":"[email protected]",
      "properties":[
      {
        "property":"company",
        "value": "Company Name"
      },
        "property":"firstname",
        "value":"John"
      },
        "property":"surname",
         "value":"Smith"
      },
        "property":"phone",
        "value":"01234567891"
      }]
  }
]

我需要输出我捕获的所有潜在客户的JSON。我通过创建一个Customer类来尝试这个：

public class Customer
{
    public string email { get; set; }
    public List<Property> properties { get; set; }

}

和一类财产：

public class Property
{
    public string property { get; set; }
    public string value { get; set; }
}

我不能为我的生活得到我追求的结果。我认为它是Customer类中的Property列表。如果我将List更改为字符串并在此处仅定义一个值，则输出正常。

请帮忙 ：（

Answer 1

此代码有效：

public class Property
    {
      public string property { get; set; }
      public string value { get; set; }
    }

    public class Customer
    {
      public string email { get; set; }
      public List<Property> properties { get; set; }

    }

    static void Main(string[] args)
    {
      string JSON = @"[
   {""email"":""test @test.com"",
      ""properties"":[
      {
        ""property"":""company"",
        ""value"": ""Company Name""
      },
       { ""property"":""firstname"",
        ""value"":""John""
      },
       { ""property"":""surname"",
         ""value"":""Smith""
      },
       { ""property"":""phone"",
        ""value"":""01234567891""
      }]
  }
]
";
      Customer[] obj = JsonConvert.DeserializeObject<Customer[]>(JSON);

    }

请注意：1。我必须在属性元素中添加缺少的开头{括号。

Answer 2

[解决了]

感谢所有提供意见的人。您的指导帮助我解决了我的问题。

        public class Customer
    {
        public string email { get; set; }
        public List<Property> properties { get; set; }
    }

    public class Property
    {
        public string property { get; set; }
        public string value { get; set; }
    }



    private void button1_Click(object sender, EventArgs e)
    {


        Customer _c = new Customer();
        _c.email = email.Text;
        _c.properties = new List<Property>();
        _c.properties.Add(new Property{ property = "company", value = company.Text });
        _c.properties.Add(new Property { property = "website", value = website.Text });
        _c.properties.Add(new Property { property = "firstname", value = firstname.Text });
        _c.properties.Add(new Property { property = "lastname", value = lastname.Text });
        _c.properties.Add(new Property { property = "phone", value = phone.Text });

        string json = JsonConvert.SerializeObject(_c, Formatting.Indented);
        outputBox.Text = json;

    }