动态SQL /异常处理-00942 - 甲骨文的PL / SQL [复制]

Question

这个问题已经在这里有一个答案：

• Oracle errors handling 2个回答

起初，我试图创建一个例外，赶上didnt存在的表（-00942）。基于来自亚历克斯和Raj反馈，我修改了代码中使用EXECUTE IMMEDIATE。这个工作在确定表但是当我纠正从“雇工”到“员工”，这是在我的数据库中存在的表的表，我本来期望的代码运行没有错误的是，当我没有使用EXECUTE IMMEDIATE的情况下。

代替生成捕获所有异常，有可能是代码通过无一例外使用EXECUTE IMMEDIATE时运行？

EXECUTE IMMEDIATE 'SELECT INTO姓氏FROM v_name员工工资WHERE = v_sal';

WHEN OTHERS THEN：g_message：= '发生其他一些错误。';

我希望的代码无一例外通过运行。

VARIABLE g_message VARCHAR2(250)

DEFINE p_sal = 12000

DECLARE 
   v_name employees.last_name%TYPE;
   v_sal employees.salary%TYPE := &p_sal;

   table_does_not_exist exception;  
   PRAGMA EXCEPTION_INIT(table_does_not_exist, -942);

BEGIN

   EXECUTE IMMEDIATE
   'SELECT last_name INTO v_name FROM employees WHERE salary = v_sal';

   DBMS_OUTPUT.put_line(v_name);


 EXCEPTION 

   WHEN table_does_not_exist then 
   :g_message := 'table dose not exist';  


   WHEN NO_DATA_FOUND THEN 
   :g_message := 'No employee with a salary of '||TO_CHAR(v_sal);  

   WHEN OTHERS THEN
   :g_message := 'Some other error occurred.';
 END;
 /
 PRINT g_message

Answer 1

试试下面：

DECLARE 
   v_name employee.emp_name%TYPE;
   v_sal employee.emp_sal%TYPE := 12000;

   table_does_not_exist exception;  
   PRAGMA EXCEPTION_INIT(table_does_not_exist, -942);

BEGIN

execute immediate
   'SELECT emp_name        
   FROM employee_l
   WHERE emp_sal = v_sal' INTO v_name;

   DBMS_OUTPUT.put_line(v_name);


 EXCEPTION 

   WHEN table_does_not_exist then 
   dbms_output.put_line( 'table dose not exist');  


   WHEN NO_DATA_FOUND THEN 
   dbms_output.put_line(  'No employee with a salary of '||TO_CHAR(v_sal));  

   WHEN OTHERS THEN
   dbms_output.put_line( 'Some other error occurred.');
 END;
 /