方法打印不正确

问题描述 投票:-4回答:1

我的方法似乎没有正确打印到printstream。只有那个说isOutComeNew()的部分似乎在打印一些东西。然而,即使这个似乎是打印输入的最后一个数字。 randOm()方法似乎也是唯一正常工作的方法。

我不知道为什么会这样。

public class Assignment3 {
    public static int number1, number2, result, newResult, newNumber1, newNumber2;
    public static int winner1 = 5, winner2 = 7, winner3 = 12;

    public static int loser1 = 2, loser2 = 4, loser3 = 11;
    public static Scanner input = new Scanner(System.in);

    public static void main(String[] args) throws Exception {

        PrintStream ps = new PrintStream("Assignment3.txt");

        promptUser();
        number1 = input.nextInt();
        System.out.println("Please enter another integer between 1-6 ");
        number2 = input.nextInt();

        do {
            ps.println("You rolled a" +number1 +  "and a " +number2);
            isValid();

            result = outCome(number1, number2);
            ps.printf("The outcome is %d \n", result);
            isOutcome();

            newNumber1 = number1 + 2;
            newNumber2 = number2 + 3;

            newNumbers();
            result = outCome(newNumber1, newNumber2);
            ps.printf("The outcome is %d \n", result);
            isOutcomeNew();

            promptUser();
            number1 = input.nextInt();
            System.out.println("Please enter another integer between 1-6 ");
            number2 = input.nextInt();

        }while ((number1 != 99) && (number2 != 95));

        randOm();
    }

    public static void promptUser() {

        System.out.println("In order to stop please enter 99 and 95 to end the game. ");
        System.out.println("Please enter an integer between 1-6. ");

    }

    public static int outCome(int x, int y) {
        int sum;
        sum = x + y;
        return (sum);
    }

    public static void isValid()throws Exception {
        PrintStream ps= new PrintStream("Assignment3.txt");
        while ((number1 < 1 || number1 > 6) || (number2 < 1 || number2 > 6)) {

            System.out.println("This set of dice rolls is invalid. Please enter another set. \n");

           System.out.println("Please reenter a number between 1 and 6. ");
            number1 = input.nextInt();
            System.out.println("Please reenter a number between 1 and 6. ");
            number2 = input.nextInt();
            System.out.printf("You rolled a %d and a %d\n", number1, number2);
                    }

    }
    // method for determining winner, loser ,or draw

    public static void isOutcome() throws Exception {
        PrintStream ps = new PrintStream("Assignment3.txt");
        // integer value for winner is 1, int value for loser is -1 and int value for draw is 0
        int winner = 1;
        int loser = -1;
        int draw = 0;

        int oldCount = 0, oldLose = 0, oldDraw = 0;
        if ((result == winner1) || (result == winner2) || (result == winner3)) {
            System.out.println(winner);
            oldCount++;

        } else if ((result == loser1) || (result == loser2) || (result == loser3)) {
            System.out.println(loser);
            oldLose++;

        } else {
            System.out.println(draw);
            oldDraw++;

        }
        System.out.printf("The amount of wins are %d \n", oldCount);
        System.out.printf("The amount of losses are %d \n", oldLose);
        System.out.printf("The amount of draws are %d \n", oldDraw);

    }

    public static void isOutcomeNew() throws Exception {
        int winner = 1;
        int loser = -1;
        int draw = 0;
        int newCount = 0, newLose = 0, newDraw = 0;
        PrintStream ps = new PrintStream("Assignment3.txt");
        if ((result == winner1) || (result == winner2) || (result == winner3)) {
            System.out.println(winner);
            newCount++;

        } else if ((result == loser1) || (result == loser2) || (result == loser3)) {
            System.out.println(loser);
            newLose++;

        } else {
            System.out.println(draw);
            newDraw++;

        }
        System.out.printf("The amount of computer wins are %d \n", newCount);
        System.out.printf("The amount of computer losses are %d \n", newLose);
        System.out.printf("The amount of computer draws are %d \n", newDraw);

    }
// 

    public static void newNumbers() throws Exception {
        PrintStream ps = new PrintStream("Assignment3.txt");

        while (newNumber1 > 6 || (newNumber2 > 6)) {
            if (newNumber1 > 6) {
                newNumber1 = (newNumber1 - 6);
                System.out.printf("The computer rolled %d \n", newNumber1);
            }
            if (newNumber2 > 6) {
                newNumber2 = (newNumber2 - 6);
                System.out.printf("The computer rolled %d \n", newNumber2);
            }
        } 
            System.out.printf("The computer rolled %d and a %d\n", newNumber1, newNumber2);

        }
java
1个回答
0
投票

只有说isOutComeNew()的部分似乎在打印一些东西。

您有许多方法可以执行此操作:

    PrintStream ps = new PrintStream("Assignment3.txt");

这些调用中的每一个都将打开输出文件的新流并截断文件。这意味着您之前写的输出将被删除。

解决方案:

  • 仅打开PrintStream一次,并将ps作为方法参数传递给方法,或者通过实例或类变量传递。
  • 当您实例化PrintStream时,在“追加”模式下打开它。你不能直接这样做,但你可以通过在追加模式下创建一个FileOutputStream,然后将其传递给PrintStream构造函数来实现。
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