如何使用RxJs将两个数组组合成单个数组，其中第二个数组的每个元素将被分配给每个对象属性的第一个数组？

Question

我有两个界面，分别是团队和公司

public interface Team {
  id: number;
  name: string;
  companyId: number;
}

public interface Company {
  id: number;
  name: string;
}

这是示例数据：

"companies": [
    {
      "id": 3,
      "name": "XSoftware",
      "location": "Nagar"
    },
    {
      "id": 5,
      "name": "Google",
      "location": "Seattle"
    },
    {
      "id": 7,
      "name": "YS",
      "location": "Dhanmondi"
    },
    {
      "id": 8,
      "name": "Amazon",
      "location": "Seattle DC"
    },
    {
      "name": "ToTD",
      "location": "Pink City",
      "id": 10
    }
]

"teams": [
    {
      "id": 1,
      "name": "Team X",
      "expertise": "Java",
      "companyId": 3
    },
    {
      "id": 2,
      "name": "Team Y",
      "expertise": "Angular",
      "companyId": 3
    },
    {
      "id": 3,
      "name": "Team Z",
      "expertise": "Spring Boot",
      "companyId": 8
    },
    {
      "id": 4,
      "name": "Team M",
      "expertise": "Node Js",
      "companyId": 5
    }
]

所以我想基于companyId将company作为属性分配给每个团队。像这样：

"teams": [
    {
      "id": 1,
      "name": "Team X",
      "expertise": "Java",
      "companyId": 3,
      "company": {
         "id": 3,
          "name": "XSoftware",
          "location": "Nagar"
       }
    },
    {
      "id": 2,
      "name": "Team Y",
      "expertise": "Angular",
      "companyId": 3,
      "company": {
         "id": 3,
          "name": "XSoftware",
          "location": "Nagar"
       }
    },
    {
      "id": 3,
      "name": "Team Z",
      "expertise": "Spring Boot",
      "companyId": 8,
      "company": {
         "id": 8,
         "name": "Amazon",
         "location": "Seattle DC"
       }
    },
    {
      "id": 4,
      "name": "Team M",
      "expertise": "Node Js",
      "companyId": 5,
      "company": {
         "id": 5,
         "name": "Google",
         "location": "Seattle"
       }
    }
]

所以我如何使用RxJs实现这一目标。我有两个可观察值，分别返回Team []和Company []的Observable。

const teams$: Observable<Team[]> = this.httpClient.get<Team[]>('/teams');
const companies$: Observable<Company[]> = this.httpClient.get<Company[]>('/companies');

所以，该怎么做？我知道可以通过命令式方式（通过使用循环，if-else等）来完成此操作，但是我想仅通过使用反应式运算符，观察者以反应式方式进行此操作。

Answer 1

正如@ShanPooShan所说，一种方法是使用forkJoin运算符。看看下面的代码片段

const teams$ = this.httpClient.get<Team[]>('/teams');
const companies$ = this.httpClient.get<Company[]>('/companies');

const teamsWithCompanies = forkJoin(teams$, companies$).pipe(
  switchMap((values: any[]) => {
    const teamsWithCompaniesResponse: TeamWithCompany[] = [];
    const teamArray = values[0];
    teamArray.forEach((team) => {
      const teamWithCompany: TeamWithCompany = {
          id: team.id,
          name: team.name,
          expertise: team.expertise,
          companyId: team.companyId,
          company: values[1].find(c => c.id === team.companyId)
      }
      teamsWithCompaniesResponse.push(teamWithCompany);
    })

    return of(teamsWithCompaniesResponse);
  })
).subscribe(response => {
  console.log('[RESPONSE]', response);
})