在Oracle中使用datediff函数时查询缓慢

问题描述 投票:0回答:1

作为标题,我具有以下代码:

 SELECT
        *
    FROM
        de.Department
    WHERE
        de.flag = 1
        AND   de.DepartmentNum IN (10,4)
        AND   de.status IN (0,-1,100)
        AND   datediff('dd',de.datequit,'30-SEP-19') > 9

datediff函数使我的查询运行非常慢(11条记录需要16秒),并且成本也很高(〜43k)。

这是我的datediff功能代码

create or replace FUNCTION       DATEDIFF 
(
  P_TYPE_DATE IN VARCHAR2 
, P_START_DATE IN TIMESTAMP 
, P_END_DATE IN TIMESTAMP 
) RETURN NUMBER AS 
  v_Result NUMBER := -1;
BEGIN

  IF P_TYPE_DATE IS NOT NULL AND P_START_DATE IS NOT NULL AND P_END_DATE IS NOT NULL THEN
    CASE UPPER(P_TYPE_DATE) 
        WHEN 'DD' THEN RETURN ROUND(TRUNC(P_END_DATE,'DD') - TRUNC(P_START_DATE,'DD'),0);
        WHEN 'HH' THEN RETURN ROUND((TRUNC(P_END_DATE,'HH') - TRUNC(P_START_DATE,'HH')) * 24,0);
        WHEN 'MI' THEN RETURN ROUND((TRUNC(P_END_DATE,'MI') - TRUNC(P_START_DATE,'MI')) * 24 * 60,0);
        WHEN 'SS' THEN RETURN ROUND((TRUNC(P_END_DATE,'MI') - TRUNC(P_START_DATE,'MI')) * 24 * 60 * 60 + extract(second from (P_END_DATE - P_START_DATE)),0);
        ELSE RETURN NULL;
    END CASE;
  END IF;
  RETURN NULL;
  EXCEPTION
    WHEN OTHERS THEN
       raise_application_error(-20001,'An error was encountered - '||SQLCODE||' -ERROR- '||SQLERRM);
END DATEDIFF;

我使用SELECT *,因为我想获得Department表中的几乎一列,因此,如果我选择一些需要的列,它就不会有任何变化。

我可以重写以提高性能和成本吗?

谢谢,谢谢!

oracle12c datediff
1个回答
0
投票

我在SQL中创建了一个名为datediff的函数作为datediff函数,先生

不要使用自定义函数,因为它们会阻止Oracle在列上使用索引;而是将列与静态值进行比较:

SELECT *
FROM   Department
WHERE  flag = 1
AND    DepartmentNum IN (10,4)
AND    status IN (0,-1,100)
AND    datequit > DATE '2019-09-30' + INTERVAL '9' DAY

AND    datequit > DATE '2019-09-30' + NUMTODSINTERVAL( 9, 'DAY' )

AND    datequit > DATE '2019-09-30' + 9
© www.soinside.com 2019 - 2024. All rights reserved.