如何在Python中使用.split为变量分配未知数量的数字输入？

Question

我的任务是创建一个程序，计算从1-100开始的数字。

我现在遇到的问题是使用.split将每个输入分配给一个变量，但是只要它超过10，用户就可以输入多少个数字。我很确定我需要使用一个某种类型的清单，但我的知识是有限的，并希望得到一些指导！

numberList = input("Enter 1 to 100 ")

Check = numberList.replace(" ","")

Answer 1

编写一个循环，连续解析输入并将识别的数字添加到列表中，直到该列表至少有10个数字。

numbers = []
while True:
    n = 10 - len(numbers)
    if n <= 0:
        break
    s = input("Enter at least {} more numbers: ".format(n))
    for v in s.split(" "):
        try:
            v = int(v)
        except ValueError:
            continue
        numbers.append(v)

Answer 2

因此，如果用户输入错误，您需要创建一个整数列表并打印错误。遵循“请求宽恕比获得许可更容易”的原则。也就是说，只需尝试将数字转换为整数，如果某些内容失败则中止任务。例如：

while True:
    userInput = input("Enter at least 10 integers between 1 and 100: ")
    try:
        numberList = [int(substring) for substring in userInput.split(" ")]
        if len(numberList) < 10:
            print("Enter at least 10 numbers")
        else:
            break
    except ValueError:
        print("You entered a non-numeric character; please try again")

最后，您想要计算每个数字的出现次数。最好的方法（在我看来）是Counter系列。有了这个，你只需要做以下事情

from collections import Counter
counter = Counter(numberList)

Answer 3

分割输入，从我猜测你的问题看起来像'1 2 45 12'，只需使用.split(' ')，正如其他人已经指出的那样。这将为您提供值的列表，但是以字符串格式。要将它们转换为整数，可以使用map，它将对列表的每个元素应用一个操作并返回一个迭代器，该迭代器可以转换为新的列表：

numberList = list(map(int, numberList))

如果该列表中的某个元素无法转换为整数，则会引发ValueError异常。使用try... except捕获它以打印您的错误消息。

对于第二部分，我将简单地遍历列表中的所有项目，使用list.count(item)（info）将返回该项目的出现次数，并将已经检查过的每个项目存储在单独的列表中以避免双重 - 检查任何。

码：

numberList = input("Enter at least 10 integers between 1 and 100: ").split(' ')
if len(numberList) < 10:
    numberList.extend(input("Enter at least {} more integers between 1 and 100: ".format(10-len(numberList))).split(' '))

try:
    numberList = list(map(int, numberList))
except ValueError:
    print("You entered a non-numeric character; please try again!")

print("You have entered {} integers.".format(len(numberList)))

checked_list = []

for i in numberList:
    if i not in checked_list:
        print("The integer {} occured {} time(s).".format(i, numberList.count(i)))
        checked_list.append(i)

输出：

Enter at least 10 integers between 1 and 100: 1 2 3 4 5 6 7
Enter at least 3 more integers between 1 and 100: 8 1 2
You have entered 10 integers.
The integer 1 occured 2 time(s).
The integer 2 occured 2 time(s).
The integer 3 occured 1 time(s).
The integer 4 occured 1 time(s).
The integer 5 occured 1 time(s).
The integer 6 occured 1 time(s).
The integer 7 occured 1 time(s).
The integer 8 occured 1 time(s).

Answer 4

你可以这样做：

numberList = input("Enter at least 10 integers between 1 and 100: ").split(" ")

if len(numberList) < 10:
    print("Enter at least 10 integers between 1 and 100: ")

要计算每个数字出现的次数：

from collections import Counter

count = Counter(numberList) # eg count = [1,4,9,7,1]
for k,v in count.items():
    print(str(k) + " appears " + str(v) + " times")