当我尝试在Timer函数中更改accumulatedTime的值时,accumulatedTime的值保持不变。
import UIKit
class WelcomeViewController: UIViewController {
@IBOutlet weak var titleLabel: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
titleLabel.text = ""
var accumulatedTime = 0.0
let logo = "Hello World"
for letter in logo {
Timer.scheduledTimer(withTimeInterval: accumulatedTime*0.1, repeats: false) { (timer) in
self.titleLabel.text?.append(letter)
accumulatedTime += 1 // increase the value of variable inside block function
}
print(accumulatedTime)
}
}
}
// Output is 0.0, 0.0, 0.0, 0.0, 0.0, 0.0...
但是如果我将“ accumulatedTime + = 1”移到Timer.scheduledTimer的块函数之外,则可以再次更改accumulatedTime的值。
import UIKit
class WelcomeViewController: UIViewController {
@IBOutlet weak var titleLabel: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
titleLabel.text = ""
var accumulatedTime = 0.0
let logo = "Hello World"
for letter in logo {
Timer.scheduledTimer(withTimeInterval: accumulatedTime*0.1, repeats: false) { (timer) in
self.titleLabel.text?.append(letter)
}
accumulatedTime += 1 // increase the value of variable outside block function
print(accumulatedTime)
}
}
}
// Output is 1.0, 2.0, 3.0, 4.0, 5.0...
我很好奇为什么我不能在Timer.scheduledTimer的块函数中更改局部变量的值,你们能帮助我了解其内部逻辑吗。谢谢
for letter in logo {
Timer.scheduledTimer(withTimeInterval: accumulatedTime*0.1, repeats: false) { (timer) in
self.titleLabel.text?.append(letter)
accumulatedTime += 1 // increase the value of variable inside block function
}
print(accumulatedTime)
}
打印语句在闭包执行之前运行...这就是为什么它们全为0 ..因为当您的打印代码在for循环中执行时它没有被设置...在闭包内使用打印语句
for letter in logo {
Timer.scheduledTimer(withTimeInterval: accumulatedTime*0.1, repeats: false) { (timer) in
self.titleLabel.text?.append(letter)
accumulatedTime += 1 // increase the value of variable inside block function
print(accumulatedTime)// print 1,2,3 .. 11
}
}
在闭包中,它的值正在更改...,并且在执行闭包时可以访问更改的值。