Java：JOptionPane.showMessageDialog的问题

Question

我正在制作一个简单的程序，它接受3个整数（n1，n2，n3）的输入，所以例如如果3个数字是6,12,4它应该返回：

Integers entered: 6,12,4  
Sum = 22  
Average = 7.33...  
Smallest = 4  
Largest = 12  

这将使用JOptionPane.showMessageDialog显示在文本框中。代码放在一个循环中，这样对于输入的每3个整数，它将返回上面显示的内容。但是，当我运行该程序时，它显示以下内容：

Integers entered: 6,6,6  
Sum = 22  
Average = 7.33...  
Smallest = 6  
Largest = 6  

n2，n3，最小值和最大值显示n1的值。这是循环中的代码，它给我带来了问题：

JOptionPane.showMessageDialog(null, title);
String num1 = JOptionPane.showInputDialog("Enter 1st integer: ");
int n1 = Integer.parseInt(num1);
String num2 = JOptionPane.showInputDialog("Enter 2nd integer: ");
int n2 = Integer.parseInt(num2);
String num3 = JOptionPane.showInputDialog("Enter 3rd integer: ");
int n3 = Integer.parseInt(num3);

int sum = n1 + n2 + n3; //find sum
double avg = (double)sum/3; //find average

//find smallest integer
int smallest = n1;
if(n2 < smallest) n2 = smallest;
if(n3 < smallest) n3 = smallest;

//find largest integer
int largest = n1;
if(n2 > largest) n2 = largest;
if(n3 > largest) n3 = largest;

JOptionPane.showMessageDialog(null, "Integers entered: " + n1 + ", " + n2 + ", " + n3 
                + "\nSum = " + sum
                + "\nAverage = " + avg
                + "\nSmallest = " + smallest
                + "\nLargest = " + largest);

如何修复它以使n2，n3，最小，最大显示正确的值？

Answer 1

您将smallest和largest的值分配回n2或n3，具体取决于评估结果......

if(n2 < smallest) n2 = smallest;
if(n3 < smallest) n3 = smallest;

//find largest integer
int largest = n1;
if(n2 > largest) n2 = largest;
if(n3 > largest) n3 = largest;

尝试更像......

if(n2 < smallest) smallest = n2;
if(n3 < smallest) smallest = n3;

//find largest integer
int largest = n1;
if(n2 > largest) largest = n2;
if(n3 > largest) largest = n3;