我对我的代码有疑问。问题是,当我说
echo $columnB
时,代码会显示我数据库中的 student_city
,但我想显示解密的密码。它只是显示错误的数据。
(还有另一个页面,我在其中加密密码,但我需要解密的密码回显
<html>
<head>
<title>insert data in database using PDO(php data object)</title>
<link rel="stylesheet" type="text/css" href="style-login.css">
</head>
<body>
<div id="main">
<h1>Login using PDO</h1>
<div id="login">
<h2>Login</h2>
<hr/>
<form action="" method="post">
<label>Email :</label>
<input type="email" name="stu_email" id="email" required="required" placeholder="[email protected]"/><br/><br />
<label>Password :</label>
<input type="password" name="stu_ww" id="ww" required="required" placeholder="Please Enter Your Password"/><br/><br />
<input type="submit" value=" Submit " name="submit"/><br />
</form>
</div>
</div>
<?php
//require ("encrypt.php");
if(isset($_POST["submit"])){
$hostname='localhost';
$username='root';
$password='';
$pdo = "college";
$student_email = $_POST["stu_email"];
$encrypt_key = "4ldetn43t4aed0ho10smhd1l";
try {
$dbh = new PDO("mysql:host=$hostname;dbname=college","root","$password");
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// Query
$statement = $dbh->prepare("SELECT student_email, student_city, AES_DECRYPT(student_password, '$encrypt_key')
AS student_password FROM students WHERE student_email = :student_email ORDER BY student_email ASC");
// Assign and execute query
$statement->bindParam(':student_email', $student_email, PDO::PARAM_STR);
$statement->setFetchMode(PDO::FETCH_ASSOC);
$statement->execute();
// Get data
while($row = $statement->fetch()) {
echo "1 ,";
//$columnA_value = $row['student_city'];
$columnB_value = $row['student_password'];
}
echo "2 ,";
echo $columnB_value;
}
catch(PDOException $e)
{
echo $e->getMessage();
}
}
?>
</body>
</html>
SELECT student_email, student_city, CAST(AES_DECRYPT(student_password, '$encrypt_key') AS char(50)) AS student_password FROM students WHERE student_email = :student_email ORDER BY student_email ASC;
尝试将其显式转换为字符串。您可以根据您的要求更改“50”。
此外,您的 echo 位于 while 循环之外,因此如果有超过 1 条记录,它将仅打印最后一条记录。