如何在并发.futures中获得已分析完成的未来的名称？

Question

[在寻找问题的答案时（链接副本中一个答案中有solution，我发现了concurrent.futures，尤其是concurrent.futures.as_completed。

我最终得到的代码（在上下文中：我需要捕获主程序从该主程序启动的线程中引发的异常）工作正常，除了我不知道如何重新附加到该程序的名称之外在concurrent.futures.as_completed中检查的功能：

concurrent.futures.as_completed

在成功/失败输出中，我知道某个方法会失败或不是异常。我不知道是哪个做了什么。

由于迭代必须在线程处理程序上进行，我找不到在

import concurrent.futures

class Checks:

    @staticmethod
    def isok():
        print("OK")

    @staticmethod
    def isko():
        raise Exception("KO")

# db will keep a map of method names in Check with the thread handler
db = {}

with concurrent.futures.ThreadPoolExecutor(max_workers=1) as executor:
    # get the names of the methods in Check, discarding the built-ion ones
    for check in [k for k in dir(Checks) if not k.startswith('_')]:
        db[check] = executor.submit(getattr(Checks, check))

# at that point I have a map of function_name_as_a_string -> thread handler
for future in concurrent.futures.as_completed([db[k] for k in db.keys()]):
    if future.exception():
        print(f"{str(future.exception())} was raised (I do not know where, somewhere)")
    else:
        print("success (again, I do not know where, exactly)")

# all the threads are finished at that point
print("all threads are done")

中将其“注入”循环中使用方法名称的方法-我该怎么做？

Answer 1

一种可能的解决方案是使用print()并创建（名称，处理程序）元组的迭代器：

zip()