我正在尝试从减去Oracle数据库中两个时间戳的输出中提取天,小时,分钟,秒。然后,我想提取提取的值并将其放在单独的列中。我可以使用substr来完成此操作,但这似乎并不高效。有没有更有效和编程的方法来提取值?下面是一个查询示例,其中包含当前和所需的输出。
示例:
SELECT
to_timestamp('2019-11-10 15:00:00', 'YYYY-MM-DD hh24:mi:ss') -
to_timestamp('2019-10-25 13:25:00', 'YYYY-MM-DD hh24:mi:ss')
as TIME_DIFF,
SUBSTR(to_timestamp('2019-11-10 15:00:00', 'YYYY-MM-DD hh24:mi:ss') -
to_timestamp('2019-10-25 13:25:00', 'YYYY-MM-DD hh24:mi:ss'), 9, 2)
as DAYS
from dual
当前输出:
TIME_DIFF | DAYS
------------------------------+-----
+000000016 01:35:00.000000000 | 16
所需的输出:
DAYS | HOUR | MIN | SS
-----+------+-----+---+
16 | 01 | 35 | 00
您可以使用extract()
从间隔中拉出所需的值:
with t as (
select to_timestamp('2019-11-10 15:00:00', 'YYYY-MM-DD hh24:mi:ss') -
to_timestamp('2019-10-25 13:25:00', 'YYYY-MM-DD hh24:mi:ss')
as TIME_DIFF
from dual
)
select
extract(day from time_diff) days,
extract(hour from time_diff) hours,
extract(minute from time_diff) minutes,
extract(second from time_diff) seconds
from t
天数|小时|分钟|秒---: ----:| ------:| ------:16 | 1 | 35 | 0
您可以看看extract()
签出此答案:TIMESTAMPDIFF in Oracle 11g?