regex（Javascript）允许忽略逗号

Question

const value = 'I am a student. My age is 5';
const regex = new RegExp('\\b' + value, 'i'); //what to add here?

console.log(regex.test('I am a student, my age is 5')); //true
console.log(regex.test('I am a student my age is 5')); //false

我想忽略,以使我的第二个字符串为true。

Answer 1

您可能想要这样的通用正则表达式：

const regex =  /^I am a \w+[.,]? My age is \d+$/i

console.log(regex.test('I am a student, my age is 5')); //should be true
console.log(regex.test('I am a student my age is 5')); //should be true
console.log(regex.test('I am a INSERTWORD my age is 5')); //should be true
console.log(regex.test('I am a student my age is 230')); //should be true

不太通用的正则表达式可能看起来像这样：

const regex =  /^I am a student[.,]? My age is 5$/i

console.log(regex.test('I am a student, my age is 5')); //should be true
console.log(regex.test('I am a student my age is 5')); //should be true
console.log(regex.test('I am a INSERTWORD my age is 5')); //should be false
console.log(regex.test('I am a student my age is 230')); //should be false

如果您想了解更多有关正则表达式的信息，请访问以下其中一项：

[https://regex101.com/ regex 101是我去regex测试的网站。

https://www.regextester.com/

https://regexr.com/