泊坞窗,构成了命令返回的代码在运行完成后始终为零

问题描述 投票:2回答:1

docker-compose返回代码在运行完成后始终为零

[nlakshmi@ROSE02T44GUH03Q database]$ docker-compose up
Recreating database_database_1 ... done
Attaching to database_database_1
database_1  | + mkdir -p -m 0755 /opt/adp/logs/db_tester/rpm/installs/
database_1  | + '[' -z abcd ']'
database_1  | + /root/bin/generateDBConfigData_FromManifest.sh abcd
database_1  | /tmp/manifest_02042019_143116.txt: line 1: syntax error near unexpected token `<'
database_1  | /tmp/manifest_02042019_143116.txt: line 1: `<!DOCTYPE html><html lang="en"><head><meta charset="utf-8"><meta http-equiv="X-UA-Compatible" content="IE=edge"><title>Oops, can&#39;t find that - Bitbucket</title><script>'
database_1  | Starting work......
database_1  | Starting clones.....
database_1  | Let us clone the config templates for tag
database_1  | fatal: Invalid refspec '+refs/tags/:refs/tags/'
database_1  | ERROR - prrs_repository wans't informed
database_1  | + source /tmp/abcd
database_1  | /root/bin/install_db.sh: line 43: /tmp/abcd: No such file or directory
database_1  | + '[' x == x ']'
database_1  | + echo 'ERROR - prrs_repository wans'\''t informed'
database_1  | + exit 1
database_database_1 exited with code 1


[nlakshmi@ROSE02T44GUH03Q database]$ echo $?
0

我跑docker-compose up和粘贴以上输出显示,即使容器失败,搬运工,撰写并没有用正确的错误代码退出。在这种情况下,我期待从docker-compose up非零退出代码

是什么赋予了 ?

docker docker-compose
1个回答
0
投票

要返回容器的退出代码返回到搬运工-构成了命令,通--exit-code-from SERVICE参数docker-compose up命令。

docker-compose up --exit-code-from database

假设你想返回从database服务退出代码。

注意:这也意味着,如果任何容器停止所有容器都将停止。

参考 - https://docs.docker.com/compose/reference/up/

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