将表格中的一行数据居中，以便数据在中心列对齐

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下午好，

我可以用一只手。最终我想做的是生成一个表，其中填充每行数据，使其以特定列为中心，而数据行居中位置的决定因素是属性“tag=0”。

这是源数据的xml文件：

<?xml version="1.0" encoding="UTF-8" ?>
<?xml-stylesheet type="text/xsl" href="javascript_mathmax_testbed.xsl"?>
<hall>
    <row name="a">
        <seat tag="-3">-3_seat_A1</seat>
        <seat tag="-2">-2_seat_A2</seat>
        <seat tag="-1">-1_seat_A3</seat>
        <seat tag="0">+1_seat_A4</seat>
        <seat tag="1">+2_seat_A5</seat>
        <seat tag="2">+3_seat_A6</seat>
        <seat tag="3">+4_seat_A7</seat>
    </row>
    <row name="b">
        <seat tag="-4">-4_seat_B1</seat>
        <seat tag="-3">-3_seat_B2</seat>
        <seat tag="-2">-2_seat_B3</seat>
        <seat tag="-1">-1_seat_B4</seat>
        <seat tag="0">+1_seat_B5</seat>
        <seat tag="1">+2_seat_B6</seat>
        <seat tag="2">+3_seat_B7</seat>
        <seat tag="3">+4_seat_B8</seat>
    </row>
    <row name="c">
        <seat tag="-2">-2_seat_C1</seat>
        <seat tag="-1">-1_seat_C2</seat>
        <seat tag="0">+1_seat_C3</seat>
        <seat tag="1">+2_seat_C4</seat>
        <seat tag="2">+3_seat_C5</seat>
        <seat tag="3">+3_seat_C6</seat>
        <seat tag="4">+4_seat_C7</seat>
    </row>
    <row name="d">
        <seat tag="-4">-4_seat_D1</seat>
        <seat tag="-3">-3_seat_D2</seat>
        <seat tag="-2">-2_seat_D3</seat>
        <seat tag="-1">-1_seat_D4</seat>
        <seat tag="0">+1_seat_D5</seat>
        <seat tag="1">+2_seat_D6</seat>
        <seat tag="2">+3_seat_D7</seat>
        <seat tag="3">+4_seat_D8</seat>
        <seat tag="4">+5_seat_D9</seat>
    </row>
    <row name="e">
        <seat tag="-2">-2_seat_E1</seat>
        <seat tag="-1">-1_seat_E2</seat>
        <seat tag="0">+1_seat_E3</seat>
        <seat tag="1">+2_seat_E4</seat>
        <seat tag="2">+3_seat_E5</seat>
    </row>
    <row name="f">
        <seat tag="0">+1_seat_E1</seat>
        <seat tag="1">+2_seat_E2</seat>
        <seat tag="2">+3_seat_E3</seat>
        <seat tag="3">+4_seat_E4</seat>
        <seat tag="4">+5_seat_E5</seat>
    </row>
    <row name="g">
        <seat tag="-4">-4_seat_E1</seat>
        <seat tag="-3">-3_seat_E2</seat>
        <seat tag="-2">-2_seat_E3</seat>
        <seat tag="-1">-1_seat_E4</seat>
        <seat tag="0">+1_seat_E5</seat>
    </row>
</hall>

我的方法可能不是最好的，但我追求的是从属性为“tag=0”的同级中找到每个“行”中先前同级“座位”的数量。然后找到每行的这些兄弟姐妹的最大值是多少，并使用它来相应地移动数据。

这就是我一直在寻找的最终结果：

这是我迄今为止提出的 xsl 样式表：

<?xml version="1.0" encoding="UTF-8"?>
<!--XSLT 1.0 - http://www.CraneSoftwrights.com/training -->
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xsl:version="1.0"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    xmlns:inr="http://mycompany.com/mynamespace">

    <xsl:variable name="STAtotal" select="count(/hall/row)"/>

    <xsl:variable name="Seattotal" select="count(/hall/row/seat)"/>

    <!--Attempt_2
        <xsl:for-each select="/hall/row/seat[@tag='0']">
        <xsl:sort select="count(preceding-sibling::seat[@tag='0'])" order="descending" data-type="number"/>
        <xsl:if test="position()=last()">
            <xsl:variable name="OSLeft" select="."/>
        </xsl:if>
    </xsl:for-each>
    Attempt_2-->

    <head>
        <title>Seating_Arrangement_testbed</title>
    </head>
    <body>
        <h2>Seating Arrangement</h2>


        <table summary="greatest position of CL" border="1">

            <tr align="center">
                <th/>
                <th>
                    <b>5th Left Lane</b>
                </th>
                <th>
                    <b>4th Left Lane</b>
                </th>
                <th>
                    <b>3th Left Lane</b>
                </th>
                <th>
                    <b>2th Left Lane</b>
                </th>
                <th>
                    <b>1th Left Lane</b>
                </th>
                <th>
                    <b>1th Right Lane</b>
                </th>
                <th>
                    <b>2th Right Lane</b>
                </th>
                <th>
                    <b>3th Right Lane</b>
                </th>
                <th>
                    <b>4th Right Lane</b>
                </th>
                <th>
                    <b>5th Right Lane</b>
                </th>
            </tr>

            <xsl:for-each select="/hall/row">
                <tr align="right">
                    <td>
                        <xsl:value-of select="@name"/>
                    </td>
                    <xsl:for-each select="./seat">
                        <td>
                            <xsl:value-of select="."/>
                        </td>
                    </xsl:for-each>
                </tr>
            </xsl:for-each>

            <tr>
                <xsl:value-of select="$STAtotal"/>
            </tr>

            <tr>
                <xsl:value-of select="$Seattotal"/>
            </tr>

            <!--Attempt_2
            <tr>
                <xsl:value-of select="$OSLeft"/>
            </tr>
            Attempt_2-->

            <tr>
                <xsl:for-each select="/hall/row/seat[@tag='0']">
                    <xsl:sort select="count(preceding-sibling::seat[@tag='0'])" order="descending" data-type="number"/>
                    <xsl:if test="position()=last()">
                        <xsl:value-of select="count(preceding-sibling::seat)+1"/>
                    </xsl:if>
                </xsl:for-each>
            </tr>


        </table>

    </body>

    <!--
<msxsl:script implements-prefix="inr" language="JScript">        
            function CLPosition(position, STAtotal)
            {
                // Make sure we have a valid number
                if (!isNaN(n))
                {   
                   
                }
                return "";
             }
</msxsl:script>
-->

</html>

找到这个值的最佳方法是什么？我在想如果我能使用 xslt 和 xpath 获取并存储它就好了，但我不知道这是否可能？也许我需要将 javascript 合并到样式表中才能得到我想要的东西？

使用我的样式表，我相信我已经获得了我正在寻找的值，但我无法将其存储为变量。如果你打开我的样式表，你会看到注释掉的代码“

xpath xslt xslt-1.0
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