将immutable.js对象传递给Ramda函数不起作用 - 不调用管道函数

问题描述 投票:0回答:1

我继承了使用immutable.js实现的redux存储(存储对象是Map)。

当我尝试通过pipe ramda商店时,它不起作用:

  import { pipe, tap } from 'ramda';

  it.only('should handle data loading', () => {
    const initialState = home(); // it returns map
    const fn = pipe(
      tap(x => {
        console.log('i am inside tap', x);
      })
    );
    console.log('this is initialState', initialState); // prints state to console correctly
    fn('wtf');          // works - tap is called
    fn(initialState);   // does not work - tap is not called
  });

你知道为什么fn(initialState)不工作吗?

immutable.js ramda.js
1个回答
1
投票

tap似乎有问题。它似乎已在最近几个版本中引入。以下两个片段之间的唯一区别是第一个使用Ramda 0.24而第二个使用Ramda 0.26.1。在那些之间,tap似乎已经破裂。虽然它适用于某些值,但它不适用于Immutable。

你能和Ramda项目一起raise an issue吗?

const {Map} = immutable
const {tap, pipe, map} = ramda
const square = n => n * n;
const home = () => new Map({foo: 1, bar: 2, baz: 3});

const fn = pipe(
  tap(console.log),
  map(square),
  tap(console.log),
);

const initialState = home();

fn(initialState);   // does not work - tap is not called
<script src="https://bundle.run/[email protected]"></script>
<script src="https://bundle.run/[email protected]"></script>

const {Map} = immutable
const {tap, pipe, map} = ramda
const square = n => n * n;
const home = () => new Map({foo: 1, bar: 2, baz: 3});

const fn = pipe(
  tap(console.log),
  map(square),
  tap(console.log),
);

const initialState = home();

fn(initialState);   // does not work - tap is not called
<script src="https://bundle.run/[email protected]"></script>
<script src="https://bundle.run/[email protected]"></script>
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