解码/解密APDU响应Java Card

Question

我使用smartcardio库通过Java与智能卡进行通信。我从卡得到响应然后我想解码对文本的响应，它有点复杂。

示例：

1. 我选择卡上的文件。
2. 从文件中获取二进制响应。
3. 读取对控制台的响应。

回复看起来：

ResponseAPDU: 145 bytes, SW=9000

Hex : 13E013A801C800001AB4138E03931BC6142B1C3214371C5114531C5B04FA24FB0026001252AE42800554003E200005621D670012002252AF9400055502C518001083188700B2195501C91BEB04601C6904FC1D660022003652B0E580055601AF180010561875108F189200941B9213CA1BD613D81BDB143E1C4314481C4A144F04511CA315261D2D656B0036001A529000

Binary:  10011111000000001001110101000000000011100100000000000000000000001101010110100000100111000111000000011100100110001101111000110000101000010101100011100001100100001010000110111000111000101000100010100010100110001110001011011000001001111101000100100111110110000000000100110000000000001001001010010101011100100001010000000000001010101010000000000001111100010000000000000000001010110001000011101011001110000000000010010000000000010001001010010101011111001010000000000000001010101010100000010110001010001100000000000000100001000001100011000100001110000000010110010000110010101010100000001110010010001101111101011000001000110000000011100011010010000010011111100000111010110011000000000001000100000000000110110010100101011000011100101100000000000010101010110000000011010111100011000000000000001000001010110000110000111010100010000100011110001100010010010000000001001010000011011100100100001001111001010000110111101011000010011110110000001101111011011000101000011111000011100010000110001010001001000000111000100101000010100010011110000010001010001000111001010001100010101001001100001110100101101011001010110101100000000001101100000000000011010010100101001000000000000

After execute : 
System.out.println("Response : " + new String(r.getData()));

new String(r.getBytes(), 0, r.getBytes().length, "UTF8")); --> give me almost the same result.

I get : 
���  ����+27QS[�$� & R�B�T >  bg  "R�� U� �� �U��`i�f " 6R���V� Vu�� ������>CHJOQ�&-ek 6 R� 

是否有不同的方法来解码从卡到文本的响应？我从卡片得到回复真是太棒了，但如果我不知道我得到了什么就没用了。我发现的解码apdu响应的大多数解决方案都很简单，但是这个解决方案还不够。

还尝试通过检查所有字符集来解码响应：

        SortedMap<String,Charset> charsets = Charset.availableCharsets();
        Iterator i = charsets.entrySet().iterator();

        while (i.hasNext())
        {
            Map.Entry m = (Map.Entry)i.next();
            String key = (String)m.getKey();

            System.out.println("Response charset " + key + " : " + new String(r.getBytes(), 0, r.getBytes().length, key));
        }

Answer 1

Read Binary可能很容易（即通常）返回非文本数据。这取决于应用程序的规范。如果没有其他信息，卡符合哪种规格，以及哪个文件，我们的猜测并不比你的好。注意，智能卡通常使用称为BER-TLV的结构化数据格式。首先，尝试获取ISO 7816，第4部分进行介绍。