我有两个字符串列表，第一个列表包含每个元素对应的第二个列表的ID。清单的定义，
IdsList ["Id1","Id2"]
ShippingsNoList ["n1,n2..","t1,t2"]
意思是n1,n2->Id1, t1,t2->Id2
IdsList格式 - > A-date-B ShippingNumbersList格式 - > number1,number2,etc.
我的目的是将两个列表和返回结果组合为字符串。如果我发现ShippingNumber等于另一个ShippingNumber并且他们的Id的日期也应该匹配，那么我应该采用运输编号和相关的ID。一个发货编号可能已经分配了多个ID，哪个日期相同。例：
IdsList=["A-28.03.18-B",
"S-17.05.18-G",
"L-17.05.18-P",
"M-28.03.18-T",
"B-17.05.18-U"]
ShippingNumbersList=["100,200,300",
"100,900",
"200,300,100",
"100,900,300",
"100,300"]
预期结果：
100-> A-28.03.18-B,M-28.03.18-T
300-> A-28.03.18-B,M-28.03.18-T
100-> S-17.05.18-G,L-17.05.18-P,B-17.05.18-U
300-> L-17.05.18-P, B-17.05.18-U
试试这个LINQ“美女”吧。
var idsList = new string[]
{
"A-28.03.18-B",
"S-17.05.18-G",
"L-17.05.18-P",
"M-28.03.18-T",
"B-17.05.18-U"
};
var shippingNumbersList = new string[]
{
"100,200,300",
"100,900",
"200,300,100",
"100,900,300",
"100,300"
};
var data = idsList
.Zip(shippingNumbersList, (x, y) =>
{
//parse the entry of the idsList ('x') in a dateTime
var date = DateTime.Parse(x.Split("-")[1]); //<-- may need to use DateTime.ParseExact(x.Split('-')[1], "dd.MM.yy", CultureInfo.InvariantCulture) - depending on the culture you are using, this will now work on any machine
//parse the entry of the shippingNumbersList ('y') in a IEnumerable<int>
var numbers = y.Split(",").Select(int.Parse);
//make a IEnumerable of the two different data, consisting of (Id, Date, ShippingNumber) <- a single ShippingNumber, thats why we call numbers.Select
return numbers.Select(number => (Id: x, Date: date, ShippingNumber: number));
}) //<-- use ZIP to combine the two lists together
.SelectMany(x => x) //<-- use SELECTMANY to get a flat list of each "id" with the x number of "shippingNumberList"
.GroupBy(x => (Date: x.Date, ShippingNumber: x.ShippingNumber)) //<-- use GROUPBY for the Date and ShippingNumber
.Where(x => x.Count() > 1) //<-- use WHERE to filter those who only have 1 entry in a group consisting of Date+ShippingNumber
.Select(x => x.Key.ShippingNumber + "-> " + string.Join(",", x.Select(y => y.Id))) //<-- use SELECT to resolve the group to a string, there the Key is the combined Date + ShippingNumber and the Value is the flatList of that group
.ToList(); //<-- use TOLIST to make a List out of the IEnumerable
不得不修复一些东西让它在dotnetfiddle上运行，但在这里你去：https://dotnetfiddle.net/bKpUDz
这是另一个经过测试的解决方案：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Data;
using System.Text.RegularExpressions;
namespace ConsoleApplication100
{
class Program
{
static void Main(string[] args)
{
List<string> IdsList = new List<string>() {
"A-28.03.18-B",
"S-17.05.18-G",
"L-17.05.18-P",
"M-28.03.18-T",
"B-17.05.18-U"
};
List<string> ShippingNumbersList = new List<string>() {
"100,200,300",
"100,900",
"200,300,100",
"100,900,300",
"100,300"
};
var results = Shipping.MergeList(IdsList, ShippingNumbersList);
}
}
public class Shipping
{
public static object MergeList(List<string> ids, List<string> numbers)
{
string pattern = @"\w-(?'day'[^\.]+)\.(?'month'[^\.]+)\.(?'year'[^-]+)";
List<KeyValuePair<DateTime, string>> idDates = new List<KeyValuePair<DateTime,string>>();
foreach(string id in ids)
{
Match match = Regex.Match(id,pattern);
idDates.Add(new KeyValuePair<DateTime, string>( new DateTime(2000 + int.Parse(match.Groups["year"].Value), int.Parse(match.Groups["month"].Value), int.Parse(match.Groups["day"].Value)), id));
}
var groups = idDates.SelectMany((x, i) => numbers[i].Split(new char[] {','}).Select(y => new { idDate = x, number = y })).ToList();
var groupDates = groups.GroupBy(x => new { date = x.idDate.Key, number = x.number }).ToList();
var results = groupDates.Select(x => new { number = x.Key.number, ids = x.Select(y => y.idDate.Value).ToList() }).ToList();
return results;
}
}
}
数据：
var IdsList =new string[] {"A-28.03.18-B",
"S-17.05.18-G",
"L-17.05.18-P",
"M-28.03.18-T",
"B-17.05.18-U" };
var ShippingNumbersList =new string[] {"100,200,300",
"100,900",
"200,300,100",
"100,900,300",
"100,300" };
取得成果：
//normalizing data and make a list of joined columns
var normalizedlist = IdsList
.Select((Ids, index) => new { Ids = Ids, ShippingNumbers = ShippingNumbersList[index].Split(',') })
.ToList();
//for each distinct ShippingNumber find and write respective Id
foreach (var ShippingNumber in normalizedlist.SelectMany(x=>x.ShippingNumbers).Distinct())
{
//fitering and then grouping by date
var filtered = normalizedlist.Where(y => y.ShippingNumbers.Contains(ShippingNumber))
.GroupBy(y => y.Ids.Split('-')[1])
.Where(y => y.Count() > 1)
.Select(y => y.Select(z=>z.Ids));
foreach (var date in filtered)
{
Console.WriteLine($"{ShippingNumber}>>{string.Join(",",date.ToArray())}");
}
}
输出：
100>>A-28.03.18-B,M-28.03.18-T
100>>S-17.05.18-G,L-17.05.18-P,B-17.05.18-U
300>>A-28.03.18-B,M-28.03.18-T
300>>L-17.05.18-P,B-17.05.18-U