我需要检查员工在休息期间是否已经退房。为此,我需要查看是否存在[[time,其中Door Name
为RDC_OUT-1
在间隔[12:15:00; 14:15:00]
import pandas as pd
df_by_date= pd.DataFrame({'Time':['01/02/2019 07:02:07', '01/02/2019 10:16:55', '01/02/2019 12:27:20', '01/02/2019 14:08:58','01/02/2019 15:32:28','01/02/2019 17:38:54'],
'Door Name':['RDC_OUT-1', 'RDC_IN-1','RDC_OUT-1','RDC_IN-1','RDC_OUT-1','RDC_IN-1']})
df_by_date['Time'] = pd.to_datetime(df_by_date['Time'])
df_by_date['hours']=pd.to_datetime(df_by_date['Time'], format='%H:%M:%S').apply(lambda x: x.time())
print('hours \n',df_by_date['hours'])
out = '12:15:00'
inn = '14:15:00'
pause=0
for i in range (len(df_by_date)):
if (out < str((df_by_date['hours'].iloc[i]).where(df_by_date['Door Name'].iloc[i]=='RDC_IN-1')) < inn) :
pause+=1
print('Break outside ')
else:
print('Break inside')
运行上面的代码时,出现此错误:
if (out < ((df_by_date['hours'].iloc[i]).where(df_by_date['Door Name'].iloc[i]=='RDC_OUT-1')) < inn) :
[AttributeError:'datetime.time'对象没有属性'where']
DataFrame / Series时,您一次选择一个单元格。
您正在选择的单元格的类型为datetime.time
但是,where
仅与完整的[[DataFrame / Series
例如,
sub_df = df_by_date['hours'].where(condition)
然后要计数,您可以使用len(sub_df)