我正在尝试将句子中的一个单词反转。
例如:arr = ['p','e','r','f','e','c','t','','m','a','k','e','s','','实践' ]应该是['p','r','a','c','t','i','c','e','','m','a','k','e','s','','p','e','r','f','e','c','t']
我写了以下代码,将整个数组颠倒然后将每个单词颠倒
def reverse_words(arr):
def mirrorReverse(arr,start,end):
while(start<end):
tmp=arr[start]
arr[start]=arr[end]
arr[end]=tmp
start+=1
end-=1
n=len(arr)
mirrorReverse(arr,0,n-1)
for i in range(len(arr)):
if arr[i]==' ' and start==0: #first word
mirrorReverse(arr,start,i-1)
start=i+1
elif i==len(arr)-1: #last word
mirrorReverse(arr,start,i)
elif arr[i]==' ' and start!=None: #middle
mirrorReverse(arr,start,i-1)
start=i+1
return arr
这很好,可以输出所需的答案,但是当我使用其他示例时,它不起作用:
test 1: [“ a”,“”,“”,“ b”]预期:[“ b”,“”,“”,“ a”]实际:['a','' ,'','b']
test2:
[“ y”,“ o”,“ u”,“”,“ w”,“ i”,“ t”,“ h”,“”,“ b”,“ e”,“”,“ f “,” o“,” r“,” c“,” e“,”“,” t“,” h“,” e“,”“,” m“,” a“,” y“]输出:['y','o','u','','w','i','t','h',',','b','e',',','f','o','r','c','e',','t',' H','e','','m','a','y']
尽管test2与上面的主要示例相似,但效果很好。任何帮助
您只需要返回反向列表吗?
您可以使用ls[::-1]
def reverse_words(arr):
return arr[::-1]
reverse_words(["a"," "," ","b"])
# ['b', ' ', ' ', 'a']
reverse_words(["y","o","u"," ","w","i","t","h"," ","b","e"," ","f","o","r","c","e"," ","t","h","e"," ","m","a","y"])
# ['y', 'a', 'm', ' ', 'e', 'h', 't', ' ', 'e', 'c', 'r', 'o', 'f', ' ', 'e', 'b', ' ', 'h', 't', 'i', 'w', ' ', 'u', 'o', 'y']
这里是拆分和合并的一种方法:
from itertools import chain
list(chain.from_iterable(' '.join(''.join(arr).split()[::-1])))
# ['p', 'r', 'a', 'c', 't', 'i', 'c', 'e', ' ', 'm', 'a', 'k', 'e', 's', ' ',
# 'p', 'e', 'r', 'f', 'e', 'c', 't']