为什么在此代码中使用fgets时会跳过用户输入？

Question

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct
{
    char* title;
    float price;
} Book;

void Display(Book[], int);

int main()
{
    int n;
    printf("How many books would you like to create?\n");
    scanf("%d", &n);

    Book *books = malloc(n * sizeof(*books));

    if (books == NULL)
    {
        printf("ERROR: Out of memory. \n");
        return 1;
    }

    for (int i = 0; i < n; i++)
    {
        books[i].title = malloc(50);

        if (books[i].title == NULL) {
                printf("No memory\n");
                return 1;
            }

        printf("Please enter a title for book %d\n", (i+1));

        fgets(books[i].title, 50, stdin);

        if ((strlen(books[i].title) > 0) && (books[i].title[strlen (books[i].title) - 1] == '\n'))
            books[i].title[strlen (books[i].title) - 1] = '\0';

        printf("Please enter a price for book %d\n", (i+1));
        scanf("%f", &books[i].price);
    }

    Display(books, n);

    for(int i = 0; i < n; i++)
        free(books[i].title);

    free(books);

    return 0;
}

void Display(Book list[], int size)
{
    for (int i = 0; i < size; i++)
    {
        printf("Title: %s, price: %.2f$. \n", list[i].title, list[i].price);
    }
}

大家好，我想拿起C，但是我在这个问题上停留了一段时间。我正在尝试制作一个程序，询问用户他想要多少本书，然后继续询问每本书的标题（包括空格）和价格。每当我运行此代码时，结果就是：

How many books would you like to create?
2
Please enter a title for book 1
Please enter a price for book 1
45.4
Please enter a title for book 2
Please enter a price for book 2
245.6
Title: , price: 45.40$. 
Title: , price: 245.60$.

为什么标题输入被跳过？

Answer 1

您的问题是这个电话：