我正试图为板球比赛模拟生成过多的值,如下所示:
Overs - > 0 - 19(总共20次) 球 - > 1 - 6(总共120,每个球有6个球)
因此,必须生成的序列将类似于0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 1.1, 1.2, 1.3, ....., 19.4, 19.5, 19.6
我可以通过使用2个嵌套循环迭代来轻松实现这一点,但由于我在RxJS中使用angular,我想以反应方式执行此操作。我想出了以下代码,它应该适用于AFAIK:
import { range } from 'rxjs';
import { map, combineAll } from 'rxjs/operators';
let overs = range(0, 20);
let balls = range(1, 6);
let ob = overs.pipe(
map((over) => balls.pipe(
map((ball) => `${over}.${ball}`)
))
).pipe(combineAll())
ob.subscribe((val) => console.log(val));
但问题是,它缺少很多价值。我得到以下输出:
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.1' ]
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.2' ]
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.3' ]
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.4' ]
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.5' ]
[ '0.6',
'1.6',
'2.6',
'3.6',
'4.6',
'5.6',
'6.6',
'7.6',
'8.6',
'9.6',
'10.6',
'11.6',
'12.6',
'13.6',
'14.6',
'15.6',
'16.6',
'17.6',
'18.6',
'19.6' ]
正如人们可以观察到的那样,所有的过度都会产生(0-19),但我们只得到每个的.6
值。只有最后一次,即19th
具有独特的价值19.1, 19.2...
我在这段代码中缺少什么?
此外,如果它有帮助,这里是上述代码的repl,以防你想尝试在浏览器中进行实验:https://repl.it/@ishankhare07/cricket-overs
你甚至不需要使用combineAll
并使用mergeMap
代替它,这使它更容易理解。
import { range } from 'rxjs';
import { map, mergeMap } from 'rxjs/operators';
let overs = range(0, 20);
let balls = range(1, 6);
let ob = overs.pipe(
mergeMap((over) => balls.pipe(
map((ball) => `${over}.${ball}`),
)),
);
ob.subscribe((val) => console.log(val));