尝试这样的事情:
我希望这个简单的演示程序在它们之间以500毫秒的间隔绘制3条线[(即绘制第一条线(暂停间隔500毫秒),绘制第二条线(暂停间隔500毫秒),绘制第3线并最终停止timer1]。] >
我已经在Visual Studio的相应(timer1属性Behavior Interval)字段中输入了500msec的值。现在,演示程序确实绘制了三行,但是500毫秒的间隔不起作用(显然是因为void timer1_Tick中缺少代码)。
有人可以帮忙吗?预先谢谢大家!
namespace WindowsFormsApp44 public partial class Form1 : Form { public Form1() { InitializeComponent(); } Graphics g; Pen p; private void Form1_Load(object sender, EventArgs e) { g = this.CreateGraphics(); p = new Pen(Color.Red, 5); } private void button1_Click(object sender, EventArgs e) { timer1.Start(); g.DrawLine(p, 200, 200, 300, 100); g.DrawLine(p, 300, 100, 400, 200); g.DrawLine(p, 200, 200, 400, 200); timer1.Stop(); } private void timer1_Tick(object sender, EventArgs e) { } }
}'''
我希望这个简单的演示程序在它们之间以500毫秒的间隔绘制3条线[(即绘制第一条线(暂停间隔500毫秒),绘制第二条线(暂停间隔500毫秒),绘制第三条线,最后...]
尝试这样的事情:
using System;
using System.Drawing;
using System.Windows.Forms;
namespace WindowsFormsApp13
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
Graphics g;
Pen p;
int tickcount = 1;
private void button1_Click(object sender, EventArgs e)
{
timer1.Enabled = true;
timer1.Start();
}
private void Form1_Load(object sender, EventArgs e)
{
g = this.CreateGraphics();
p = new Pen(Color.Red, 5);
}
private void timer1_Tick(object sender, EventArgs e)
{
switch (tickcount)
{
case 1:
g.DrawLine(p, 200, 200, 300, 100);
break;
case 2:
g.DrawLine(p, 300, 100, 400, 200);
break;
case 3:
g.DrawLine(p, 200, 200, 400, 200);
break;
default:
break;
}
tickcount++;
if (tickcount > 3)
{
timer1.Stop();
timer1.Enabled = false;
}
}
}
}
尝试这样的事情: