嘿,我是Ruby的新手,我遇到了问题。我的文件Wordlist有超过100,000个单词,如果我的hashcode等于我的文件Wordlist中的一个单词,我想用方法test_password检查,但是当我检查我的文件的最后一个单词时,需要花费很多时间来迭代它,可以请某人帮助我如何让它更快?
File.open("Wordlist.txt", "r") do |fi|
fi.each_line do |words|
text_word << words.chomp
end
end
text_word.each do |words|
if test_password(words,ARGV[0])
puts "FOUND: " + words
break
end
end
您可以使用[hash_code(word), word]
对创建一次哈希,并将结果写为JSON,YAML或数据库(例如SQLite)。如果计算此哈希需要很长时间,这是可以的,因为您只需要执行一次。接下来,您只需要读取保存的哈希值,这应该很快。
现在,检查哈希中是否有单词或哈希码应该非常快。
以下是TODO为您留下的一个小例子:
require 'json'
require 'digest/md5'
hashcodes = {}
def my_hashcode(word)
Digest::MD5.hexdigest word
end
# This part is slow, that's okay because it can be saved once and for all and doesn't depend on your input
File.open('/usr/share/dict/american-english') do |wordlist|
wordlist.each do |word|
word.chomp!
hashcodes[my_hashcode(word)] = word
end
end
#TODO: Write hashcodes to JSON file
#TODO: Read hashcode from JSON file
# This part depends on your input but is very fast:
some_hashcode = my_hashcode("test")
p hashcodes[some_hashcode]
# => "test"
p hashcodes["S0MEWEIRDH4SH"]
# => nil